Answer:
Height of shuttle at that instant = 1.17 miles
Step-by-step explanation:
Refer the given figure.
C is the position of rocket and B is the position of observer.
Here we need to find AC, that is the height of shuttle at that instant.
Using trigonometric rules on ΔABC, we have
Height of shuttle at that instant = AC = 1.17 miles
Answer:
d. Anthony rode 14 more miles per week than Malique.
Step-by-step explanation:
Anthony rode (141 mi)/(3 wk) = 47 mi/wk.
Malique rode (165 mi)/(5 wk) = 33 mi/wk.
Anthony rode more miles per week by ...
(47 -33) mi/wk = 14 mi/wk
Anthony rode 14 more miles per week than Malique.
2x+7/9=5/6 I think it the answer
Well, it is a good and interesting question
Such areas could be calculated in a single shoot and also by dividing the whole shape into other shapes and the total area would be the sum of these areas
I prefer the way of a single shoot ...
The figure represents a trapezoid:
its lower base = 21 units
its upper base = 12 units
the normal height between them = 8 units
NOW
The area of a trapezoid = [(sum of bases' lengths) ÷ 2] * height
= [(12 + 21) ÷ 2] * 8 = 132 sq units
Hope that helps
The value of x would be 5 for the model 2x+4.
Rearrange unknown terms to the left side of the equation,
Combine like terms
By calculating the sum or difference : -x = -5
Lets divide both sides of the equation by the resulting coefficient 5
So x = 5
#SPJ10
Learn more about algebra equations refer:
https://brainly.in/question/7037012
