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2 years ago

A customer buys a car for $14,500. The car loses value at a rate of 3.5%

Mathematics

2 answers:

yuradex [85]2 years ago

7 0

Answer: D because you just need to subtract 3.5% 5 times from 14,500.

Vedmedyk [2.9K]2 years ago

3 0

Answer: I’m not so sure

Step-by-step explanation:

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What are the equations

I am Lyosha [343]

Answer:

(-3,4)

(-1,4)

(-3,7)

Step-by-step explanation:

(1,1) → (1-4, 1+3) → (-3,4)

(3,1) → (3-4, 1+3) → (-1,4)

(1,4) → (1-4, 4+3) → (-3,7)

8 0

2 years ago

You have 100 feet of fencing and decide to make a rectangular garden. What is the largest area enclosed

k0ka [10]

Answer:

625 ft^2

Step-by-step explanation:

Given

$P = 100$ --- perimeter

Required

The largest area

The perimeter is calculated as:

$P = 2 * ( L + W)$

So, we have:

$2 * ( L + W) = 100$

Divide both sides by 2

$L + W = 50$

Make L the subject

$L = 50 - W$

The area is calculated as:

$A= L * W$

Substitute $L = 50 - W$

$A= (50 - W) * W$

Open bracket

$A = 50W - W^2$

Differentiate with respect to W

$A' = 50 -2W$

Set to 0; to get the maximum value of W

$50 - 2W = 0$

Collect like terms

$-2W = -50$

Divide by -2

$W = 25$

So, the maximum area is:

$A = 50W - W^2$

$A = 50 * 25 - 25^2$

$A = 1250 - 625$

$A = 625$

3 0

2 years ago

A multiple-choice examination has 20 questions, each with five possible answers, only one of which is correct. Suppose that one

kari74 [83]

Answer:

The probability that the student answers at least seventeen questions correctly is $8.03\times 10^{-10}$ .

Step-by-step explanation:

Let the random variable X represent the number of correctly answered questions.

It is provided all the questions have five options with only one correct option.

Then the probability of selecting the correct option is,

$P(X)=p=\frac{1}{5}=0.20$

There are n = 20 question in the exam.

It is also provided that a student taking the examination answers each of the questions with an independent random guess.

Then the random variable can be modeled by the Binomial distribution with parameters n = 20 and p = 0.20.

The probability mass function of X is:

$P(X=x)={20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x};\ x =0,1,2,3...$

Compute the probability that the student answers at least seventeen questions correctly as follows:

$P(X\geq 17)=P (X=17)+P (X=18)+P (X=19)+P (X=20)$

$=\sum\limits^{20}_{x=17}{{20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x}}\\\\=0.00000000077+0.000000000032+0.00000000000084+0.000000000000042\\\\=0.000000000802882\\\\=8.03\times10^{-10}$

Thus, the probability that the student answers at least seventeen questions correctly is $8.03\times 10^{-10}$ .

4 0

3 years ago

Help! Got it wrong after trying first time and need helppp !

finlep [7]

We are given the equation:

DA - 2qA = B³

Taking 'A' common on the LHS

A(D - 2q) = B³

Dividing both sides by (D - 2q)

A = B³ / (D - 2q)

5 0

2 years ago

Please help pleaseeeee

Rudik [331]

Answer:

B 1/2

Step-by-step explanation:

The probability of rolling an even number on a fair, six-sided die is 3/6 = 1/2, which results from three of the six possibilities of {1, 2, 3, 4, 5, 6} being even numbers.

3 0

3 years ago