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ra1l [238]
3 years ago
5

PLEASEE HELP IM BEGGING YOU

Mathematics
1 answer:
devlian [24]3 years ago
6 0

Answer: god it's hard, but i will try

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Please let me know how to factor thisss. and give me the steps.
madam [21]
You have to find first the discriminant
∆=8^2-4*(-1) *(-7) =36
x=(-8±√36) /-2=(-8±6)/-2=4±3=1 or 7
So x(1)=1 or x(2)=7
-x^2+8x-7=[x-x(1) ][x-x(2) ]=(x-1) (x-7)
6 0
4 years ago
Math help please im so confused
Len [333]

Answer:

Angle 3 is 49 degrees

=============================

Explanation:

Angle 1 is 50 degrees and angle 2 is 48 degrees. Added up, they total to 98 degrees. This is angle DEF.

Angle DEF is congruent to angle ABC because they are alternate exterior angles and because lines m and n are parallel

We are told that angle ABC is bisected (aka cut in half) because of line s; which means that the angles labeled "4" and "5" are exactly half that of angle ABC = 98 degrees

Therefore, angle 4 is 98/2 = 49 degrees and so is angle 3 (due to angles 3 and 4 being vertical angles; angle 3 = angle 4)

4 0
3 years ago
Work out the area of this quarter circle of radius 8cm, Give you answer in terms of pi
oee [108]

Answer:

The area of the quarter circle is 16\pi\ cm^{2}

Step-by-step explanation:

we know that

The area of a quarter circle is equal to

A=\frac{1}{4}\pi r^{2}

we have

r=8\ cm

substitute the value

A=\frac{1}{4}\pi (8)^{2}

A=16\pi\ cm^{2}

3 0
3 years ago
Which is less, 3 or 30? Explain how you know
r-ruslan [8.4K]

Answer:

3

Step-by-step explanation:

3 is closer to 0

7 0
3 years ago
Read 2 more answers
Please help this is my last question for this page and I'm stuck on it
Lena [83]

put a 1 under the 13, so it is 13/1, and 5 5/6, turn it into an improper fraction by multiplying 5x6=30. then 30+5, which is 35. so just keep the denominator, which would be 35/6. so you would have 13/1 - 35/6. you need the same denominator, so see what both 1 and 6 would fit into. which is 6. so 13x6 which is 78, so 78/6 - 35/6, so 78-35 is 43. so 43/6, then simplify, which is 7 1/6

6 0
3 years ago
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