What is the slope of the line whose equation is 4y-6x+16=0
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Since it is perpendicular to y=3x-1, the slope must be a negative reciprocal.
there the slope of the perpendicular line is
So now we have,
To find b, we use the point that the line passes through and substitute it to the y and x values.
which would give us b=5/3
Therefore, the equation of the line is
there the slope of the perpendicular line is
So now we have,
To find b, we use the point that the line passes through and substitute it to the y and x values.
which would give us b=5/3
Therefore, the equation of the line is
First, we need to equalize the denominator. If the denominator multiplies by (x+1), so does the numerator. If the denominator multiplies by (x-1), so does the numerator.
Look into my attachment at the second row.
Second, because the first fraction and the second fraction have the same denominator, you can join them into one fraction.
Look into my attachment at the third row.
Third, simplify the numerator.
Look into my attachment at the fourth to the fifth row
Fourth, simplify the denominator.
Look into my attachment at the sixth to the seventh row.
Look into my attachment at the second row.
Second, because the first fraction and the second fraction have the same denominator, you can join them into one fraction.
Look into my attachment at the third row.
Third, simplify the numerator.
Look into my attachment at the fourth to the fifth row
Fourth, simplify the denominator.
Look into my attachment at the sixth to the seventh row.