Answer:
y = -3/2 x +13
Step-by-step explanation:
We want our line to be perpendicular to
y = 2/3 x -1
The slope of this line is 2/3 (since it is written in the form y = mx+b and m is the slope)
Perpendicular lines have negative reciprocal slopes
m = -(3/2)
The slope of our new line is -3/2
We can use point slope form of the equation
y-y1 - m (x-x1)
y - 7 = -3/2 (x-4)
Distribute
y-7 = -3/2x +6
Add 7 to each side
y-7+7 = -3/2 x +6+7
y = -3/2 x +13
(AB)^2 + (2 m)^2 = (8 m)^2, or
(AB)^2 + 4 m^2 = 64 m^2, or (AB)^2 = 60 m^2.
Taking the square root of both sides, (length of AB) = + 2sqrt(15) (answer)
The mean hours worked is 9 hours.
Answer:
Step-by-step explanation:
x(3x+2)=16
3x²+2x-16=0
3x²+8x-6x-16=0
x(3x+8)-2(3x+8)=0
(3x+8)(x-2)=0
either 3x+8=0
x=-8/3(rejected as width can't be negative)
x-2=0
x=2
so width=2
length=3×2+2=6+2=8
Answer:
V2=-20.0155m/s
Step-by-step explanation:
To answer this question we will use the principle of conservation of momentum which is
MtVt=M1V1+M2V2
1) let's find the initial velocity.
We will use,
v=a*t
v=10m/s2*2s = 20 m/s
d=vot+1/2*a*t2
d=0+1/2*10*4
d=20m
2) For the speed of the lighter piece we use,
v22=v12+2ad
0=v12+2*-9.81*(530-20)
v12=10006.2
v1=100.031m/s
3) Computing this in our conservation of momentum equation it will be-
MtVt=M1V1+M2V2
1500kg*20m/s=(1500*1/3)kg*100.031m/s + (1500*2/3)+V2
30000=50015.5+1000V2
Therefore V2=-20.0155m/s.
