First, let's establish a ratio between these two values. We'll use that as a starting point. I personally find it easiest to work with ratios as fractions, so we'll set that up:

To find the distance <em>per year</em>, we'll need to find the <em>unit rate</em> of this ratio in terms of years. The word <em>unit</em> refers to the number 1 (coming from the Latin root <em>uni-</em> ); a <em>unit rate</em> involves bringing the number we're interested in down to 1 while preserving the ratio. Since we're looking for the distance the fault line moves every one year, we'll have to bring that 175 down to one, which we can do by dividing it by 175. To preserve our ratio, we also have to divide the top by 175:

We have our answer: approximately
0.14 cm or
1.4 mm per year
Answer:
Step-by-step explanation:
n mathematics, a set having an addition that must be commutative, and associative, and a multiplication that must be associative
Answer:
D. The area to the left of 7.5
Step-by-step explanation:
If fewer than 8 passengers do not show up for a flight, then at most 7 passengers do not show up for a flight. Therefore, applying continuity correction, the area under the curve must comprehend from zero to seven passengers not showing up, but not the 8th passenger. Thus, the area must be to the left of 7.5.
The answer is D. The area to the left of 7.5.