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brilliants [131]
3 years ago
6

An experimenter has prepared a drug dosage level that she claims will induce sleep for 80% of people suffering from insomnia. Af

ter examining the dosage, we feel that her claims regarding the effectiveness of the dosage are inflated. In an attempt to disprove her claim, we administer her prescribed dosage to 20 insomniacs and we observe Y , the number for whom the drug dose induces sleep. We wish to test the hypothesis H0 : p = 0.8 versus the alternative, Ha : p < 0.8. Assume that the rejection region {y ≤ 12} is used. (a) In terms of this problem, what is a type I error?
Mathematics
1 answer:
Digiron [165]3 years ago
8 0

Answer:

This type of error would lead to the conclusion that the dosage level is less effective than it really is.

Step-by-step explanation:

A Type I error happens when we reject the null hypothesis even when it is true.

In this case, this would happens when the sample taken gives results that end by pure chance in the rejection region, and nont because the null hypothesis is not true.

This type of error would lead to the conclusion that the dosage level is less effective than it really is.

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Westkost [7]
I hope someone solves your problem :)
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Ne4ueva [31]

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3 years ago
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Lina20 [59]

Option D: Two irrational solutions

Explanation:

The equation is 17+3 x^{2}=6 x

Subtracting 6x from both sides, we have,

3x^{2} -6x+17=0

Solving the equation using quadratic formula,

x=\frac{6 \pm \sqrt{36-4(3)(17)}}{2(3)}

Simplifying the expression, we get,

\begin{aligned}x &=\frac{6 \pm \sqrt{36-204}}{6} \\&=\frac{6 \pm \sqrt{-168}}{6} \\&=\frac{6 \pm 2 i \sqrt{42}}{6}\end{aligned}

Taking out the common terms and simplifying, we have,

\begin{aligned}x &=\frac{2(3 \pm i \sqrt{42})}{6} \\&=\frac{(3 \pm i \sqrt{42})}{3}\end{aligned}

Dividing by 3, we get,

x=1+i \sqrt{\frac{14}{3}}, x=1-i \sqrt{\frac{14}{3}}

Hence, the equation has two irrational solutions.

8 0
3 years ago
you are given an 8-gallon jug filled with water and also two empty jugs: one that holds 5 gallons and other that holds 3 gallons
Yanka [14]

Answer:

Step-by-step explanation:

We will use following steps to measure exactly 4 gallons of water with the help of 5 gallons and 3 gallons empty jugs.

1). Fill 3 gallons jug completely.

2). Pour this 3 gallons of water into 5 gallons jug. Now we have 3 gallons of water in 5 gallons jug and 3 gallons jug empty.

We can add 2 gallons of water in the empty space of 5 gallons jug more.

3). Fill the 3 gallons jug with the water again.

4). Pour this water into 5 gallons jug which can hold 2 gallons of water more.

Now we have 5 gallons of jug filled fully and 1 gallon water remaining in the 3 gallons jug.

5). Empty the 5 gallons jug completely.

6). Pour the remaining 1 gallon of remaining water in 3 gallons jug into 5 gallons jug.

7). Fill the 3 gallons jug completely and pour it into 5 gallon jug.

8). Finally we have 4 gallons of water in the 5 gallons jug.

8 0
3 years ago
Why does a logarithmic equation sometimes have an extraneous solution?
jonny [76]

The main reason behind this is using properties of logarithm .

like

when solving

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There you use multiplication property and make addition to multiplication then you get extraneous solution because in plenty of cases they occur

like

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But

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Same happens in case of logarithm

6 0
2 years ago
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