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vredina [299]
2 years ago
14

a store sells a 1 1/4 pound of turkey for 9 dollars what is the unit price of the turkey in the package

Mathematics
1 answer:
Ilya [14]2 years ago
6 0

Answer:

7.20 dollars

Step-by-step explanation:

1 1/4 can be expressed as 5/4 ((1*4+1) /4)

If price of 5/4 pound of turkey = $9

Price of 1 pound of turkey = $9 / (5/4)

( Same way you'd divide the price of 2 pounds by 2 to get the price of 1 pound)

$9 / (5/4) = $7.2

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Can i please get help with this question?
Aleonysh [2.5K]

1,5 . n = 13,65


We know:


1,5=\frac{15}{10}

and

13,65=\frac{1365}{100}


So,


\frac{15}{10}.n=\frac{1365}{100}


Pass \frac{15}{10} as division.


n = \frac{\frac{1365}{100}}{\frac{15}{10}}


Btw, we also know:


\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a.d}{b.c}


So,


n = \frac{\frac{1365}{100}}{\frac{15}{10}}

n = \frac{1365.10}{100.15}

n = \frac{13650}{1500}

n = \frac{91}{10}

n = 9,1

5 0
3 years ago
Solve for y.
ladessa [460]

Answer:

y = 9/b

Step-by-step explanation:

by = 9 solved for b yields y = 9/b.

7 0
3 years ago
cylinder a has a radius of 1 m and a height of 4 m cylinder b has a radius of 1 m and a height of 8 what is the ratio of the vol
ikadub [295]
Volume of A= πR².H ==> V(A)=4π m³

Volume of V =πR².H ==>V(B)=8π m³

.Ratio of A to B =(4π) /(4π) = 1/2
8 0
3 years ago
Read 2 more answers
A $120,000, 5%, 200-day note dated June 6 is discounted on October 8. The discount period is how many days?
expeople1 [14]
June: 30-6=24
July: 31
August:31
September:30
October: 8
Total=24+31+31+30+8=124 days

Discount period:
The period of time between the date a bill of exchange is drawn and the date on which payment is due.

So discount period = 200-124=76 days
5 0
3 years ago
A farmer plans to enclose two adjacent rectangular pens against a barn wall (see figure).
Licemer1 [7]

Answer: Let's assume that the pig pens need to be fenced in the way shown in the diagram above.

Then, the perimeter is given by

4

x

+

3

y

=

160

.

4

x

=

160

−

3

y

x

=

40

−

3

4

y

The area of a rectangle is given by

A

=

L

×

W

, however here we have two rectangles put together, so the total area will be given by

A

=

2

×

L

×

W

.

A

=

2

(

40

−

3

4

y

)

y

A

=

80

y

−

3

2

y

2

Now, let's differentiate this function, with respect to y, to find any critical points on the graph.

A

'

(

y

)

=

80

−

3

y

Setting to 0:

0

=

80

−

3

y

−

80

=

−

3

y

80

3

=

y

x

=

40

−

3

4

×

80

3

x

=

40

−

20

x

=

20

Hence, the dimensions that will give the maximum area are

20

by

26

2

3

feet.

A graphical check of the initial function shows that the vertex is at

(

26

2

3

,

1066

2

3

)

, which represents one of the dimensions that will give the maximum area and the maximum area, respectively.

Hopefully this helps!

Step-by-step explanation: hope this helps

3 0
3 years ago
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