Since you're only interested in x, you can use the first equation to write an expression for y that can be substituted into the second equation.
.. y = k -x
.. 2x +3(k -x) = k +1
.. -x +3k = k +1 . . . . . collect terms
.. 2k -1 -x = 0 . . . . . . subtract k+1
.. 2k -1 = x . . . . . . . . .add x
The 3rd selection is appropriate.
Step-by-step explanation:
Is there a image or any numbers because I can't see any
5 friends could got to the party
21-16=5
I think Theodosius the best measure. The outliers will not effect the measure. If you use mean, you add all the data points and divide by the number of data points. The extremes will skew the data. If you use mode, that may work also. You find the data that occurs most often.
I believe it's A. <span>Eva would have been better off selecting the 20-year term policy.
Unde current circumtances, 10-year term policy wouldn't guarantee thesafety of the kids because even after the policy ends, Eva's kids still haven't entered the age where they could find their own income (they would be 12, 13, and 15).
If Eva decided to add another 10 year despite the extra charge, The kids will be covered until they enter the productive age.</span>
