For the given equation;

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.
Let us begin by expanding the parenthesis;

Now that we have expanded the left side of the equation, we would have;

We shall now solve the resulting quadratic equation using the quadratic formula as follows;
![\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D%20%5C%5C%20%5Ctext%7BWhere%3B%7D%20%5C%5C%20a%3D9%2Cb%3D-30%2Cc%3D150%20%5C%5C%20x%3D%5Cfrac%7B-%28-30%29%5Cpm%5Csqrt%5B%5D%7B%28-30%29%5E2-4%289%29%28150%29%7D%7D%7B2%289%29%7D%20%5C%5C%20x%3D%5Cfrac%7B30%5Cpm%5Csqrt%5B%5D%7B900-5400%7D%7D%7B18%7D%20%5C%5C%20x%3D%5Cfrac%7B30%5Cpm%5Csqrt%5B%5D%7B-4500%7D%7D%7B18%7D%20%5C%5C%20x%3D%5Cfrac%7B30%5Cpm%5Csqrt%5B%5D%7B-900%5Ctimes5%7D%7D%7B18%7D%20%5C%5C%20x%3D%5Cfrac%7B30%5Cpm%5Csqrt%5B%5D%7B-900%7D%5Ctimes%5Csqrt%5B%5D%7B5%7D%7D%7B18%7D%20%5C%5C%20x%3D%5Cfrac%7B30%5Cpm30i%5Csqrt%5B%5D%7B5%7D%7D%7B18%7D%20%5C%5C%20%5Ctext%7BTherefore%3B%7D%20%5C%5C%20x%3D%5Cfrac%7B30%2B30i%5Csqrt%5B%5D%7B5%7D%7D%7B18%7D%2Cx%3D%5Cfrac%7B30-30i%5Csqrt%5B%5D%7B5%7D%7D%7B18%7D%20%5C%5C%20%5Ctext%7BDivide%20all%20through%20by%206%2C%20and%20we%27ll%20have%3B%7D%20%5C%5C%20x%3D%5Cfrac%7B5%2B5i%5Csqrt%5B%5D%7B5%7D%7D%7B3%7D%2Cx%3D%5Cfrac%7B5-5i%5Csqrt%5B%5D%7B5%7D%7D%7B3%7D%20%5Cend%7Bgathered%7D)
ANSWER:
<h2>
Greetings</h2>
Answer:
Yes, they are.
Step-by-step explanation:
<h3>1st rate)</h3>
Lets simplify both rates to the rate typer per minute.
(m is minutes)
3m = 96
Divide both sides by 3:

m = 32
So the rate is 32 words per minute.
<h3>2nd rate</h3>
5m = 160
Divide both sides by 5:

m = 32
<h3>So because the rates per minute are the same, they are equivalent.</h3>
<h2>Hope this helps!</h2>
The GCF is 36 since 36 can go into 144 (:
x
- Square <em>:</em><em>4</em><em> </em><em>sides</em><em>,</em><em>each</em><em> </em><em>side</em><em> </em><em>9</em><em>0</em><em> </em><em>degrees</em><em> </em><em>.</em><em>.</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>:each angle is 90 degrees
: 4 diagonals
- Rectangle: 4 sides..4 angles..2 diagonals..
- Rhombus : <u>4</u><u> </u><u>sides</u><u>.</u><u>.</u><u>2</u><u> </u><u>angles</u><u>.</u><u>.</u><u>.</u><u>2</u><u> </u><u>diagonals</u><u>.</u><u>.</u>
- Parallelogram : 4 sides..4 angles..2 diagonals..
- Quadrilateral: 4 sides...4 angles...4 diagonals..
<em>If</em><em> </em><em>this</em><em> answer</em><em> helps</em><em><u> you</u></em><em><u> plz</u></em><em><u> mark</u></em><em><u> as</u></em><em><u> brainlist</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
0.34
Step-by-step explanation:
Do the inverse operation so;
0.034 / 1/10 = 0.34
Now go back and subsitute,
0.34 * 1/10 = 0.034