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3 years ago

PLLSS HELP ME ty :)))

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

6 0

I think its 210 ≤ t

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Based on the side lengths given (a, b, and o, which triangles are right triangles?

Cloud [144]

Answer:

2 & 3

Step-by-step explanation:

Pythagorean Theorem is $a^2+b^2=c^2$ .

If the values given in each option satisfy the theorem, the sides will make a right triangle.

<h3>For Option One:</h3>

$4^2+6^2=8^2\\=> 4^2=16\\=> 6^2=36\\=>8^2 =64\\16+36=64\\\boxed{52\neq 64}$

The sides would not make a right triangle.

<h3>For Option Two:</h3>

$6^2+8^2=10^2\\=> 6^2 = 36\\=> 8^2=64\\=> 10^2=100\\36+64=100\\\boxed{100=100}$

The sides would make a right triangle.

<h3>For Option Three:</h3>

$5^2+6^2=\sqrt{61}^2\\ => 5^2=25\\=>6^2=36\\=>\sqrt{61}^2=61\\ 25+36=61\\\boxed {61=61}$

The sides would make a right triangle.

<h3>For Option Four:</h3>

$6^2+9^2=12^2\\=> 6^2=36\\=>9^2=81\\=>12^2=144\\36+81=144\\\boxed{117\neq 144}$

The sides would not make a right triangle.

The correct answer should be options two and three.

6 0

3 years ago

Complete the factoring,<br> 5x^2 - 40x = 5x( ) <br><br> HELP ASAP PLS!

Aleksandr-060686 [28]

Answer:

$5x(x-8)$

Step-by-step explanation:

Factor $5x$ out of $5x^{2} -40x$

8 0

3 years ago

Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following p

strojnjashka [21]

Answer:

P(X = 3) = 0.14680064

Step-by-step explanation:

Formula=============================

$p\left( X=k\right) =C^{k}_{n}p^{k}(1-p)^{n-k}\ \ ;\ k\in \left\{ 0,\ldots ,n\right\}$

……………………………………………………………………..

Given :

n = 8

p = 0.2

1 - p = 1 - 0.2 = 0.8

k = 3

Then

$p\left( X=3\right) =C^{3}_{8}(0.2)^{3}(0.8)^{5}$

$=0.14680064$

4 0

2 years ago

Solve for slope y=4x+6

Semmy [17]

Answer:

Step-by-step explanation:

y = mx+b where m is slope so the slope is 4

3 0

3 years ago

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∫ 5cos(x) - 2sec²(x) dx

daser333 [38]

$\bf \displaystyle \int [5cos(x) - 2sec^2(x)]dx\implies 5\int cos(x)dx~-~2\int sec^2(x)dx
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5sin(x)-2tan(x)+C$

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3 years ago