Answer:
Shortest Path : A-C, C-Z
Shortest possible time = 143
Step-by-step explanation:
P.S - The exact question is -
Given -
T1 = 38
T2 = 52
T3 = 63
T4 = 67
T5 = 91
T6 = 62
T7 = 64
To find - What is the shortest path and what is the shortest possible time to travel from A to Z ?
Proof -
Choices for shortest path is -
Choice 1 : A-B, B-E, E-Z ;
Choice 2 : A-C, C-Z ;
Choice 3 : A-B, B-D, D-Z
Now,
For Choice 1 : A-B, B-E, E-Z
Distance between A-B = T1 = 38
Distance between B-E = T4 = 67
Distance between E-Z = T7 = 64
So,
The distance = 38 + 67 + 64 = 169
Now,
For Choice 2 : A-C, C-Z
Distance between A-C = T2 = 52
Distance between C-Z = T5 = 91
So,
The distance = 52 + 91 = 143
Now,
For Choice 3 : A-B, B-D, D-Z
Distance between A-B = T1 = 38
Distance between B-D = T3 = 63
Distance between D-Z = T6 = 62
So,
The distance = 38 + 63 + 62 = 163
∴ By comparing we get
Shortest Path = A-C, C-Z
Shortest possible time = 143