Answer:
The confidence interval is 
Step-by-step explanation:
From the question we are told that
The sample size is n = 118
The number that gave the correct answer is k = 44
Generally the sample proportion is mathematically represented as
=> 
Generally given that the confidence level is 95% the level of significance is mathematically represented as
=> 
Generally from the normal distribution table the critical value of 
is
Generally the margin of error is mathematically represented as
=> 
=> 
Generally 95% confidence interval is mathematically represented as
=> 
=>
Answer:
the probability that no customer will arrive in the next 6 minutes = 0.36788 = 0.368
Step-by-step explanation:
If there are 10 customers per hour, this translates to 1 customer per 6 minutes
So, if there's a mean of 1 customer per 6 minutes, to obtain the probability that no customer will come in a 6 minute interval, this becomes a Poisson distribution problem.
The Poisson distribution formula is given by
P(X = x) = (e^-λ)(λˣ)/x!
where λ = mean = 1 customer per 6 minutes
x = 0 customer per 6 minutes
P(X=0) = (e⁻¹)(1⁰)/0! = 0.36788 = 0.368
Answer:
6x + 2; x = 2; 6(2) + 2 = 12 + 2 = 14
Step-by-step explanation:
Answer:
Roger can earn $510 at most.
Step-by-step explanation:
We are given the function

Which gives the earnings of Roger when he sells v videos. Since the play’s audience consists of 230 people and each one buys no more than one video, v can take values from 0 to 230, i.e.

That is the practical domain of E(v)
If Roger is in bad luck and nobody is willing to purchase a video, v=0
If Roger is in a perfectly lucky night and every person from the audience wants to purchase a video, then v=230. It's the practical upper limit since each person can only purchase 1 video
In the above-mentioned case, where v=230, then

Roger can earn $510 at most.
Work done on cart
:
W
=
6000
J
Kinetic energy of cart
:
E
K
=
6000
J
Explanation:
Work done
W
is defined as the product of force
F
and distance
s
:
⇒
W
=
F
⋅
s
Let's substitute the values of
F
and
s
into the equation:
⇒
W
=
300
N
⋅
20
m
⇒
W
=
300
kg
⋅
m s
−
2
⋅
20
m
⇒
W
=
300
⋅
20
kg
⋅
m
2
s
−
2
⇒
W
=
6000
kg
⋅
m
2
s
−
2
∴
W
=
6000
J
The gain in kinetic energy
E
K
is the same amount as the work done moving the cart:
∴
E
K
=
6000
