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kipiarov [429]
3 years ago
7

Use <,>,or= to compare the ratios 36 ? 6 60 10

Mathematics
1 answer:
katen-ka-za [31]3 years ago
4 0

Answer:

36/60 =6/10

Step-by-step explanation:

36/60 = 0.6

6/10=0.6

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Find the sum of the first 21 terms of the sequence 5,9, 13, 17, 21, ...
Scorpion4ik [409]
21(5+85)/2= 21•45= 945
8 0
3 years ago
Given that ∠ABD = 71°, which equation could be used to solve problems involving the relationships between ∠DBC and ∠ABC?
dexar [7]

Step-by-step explanation:

one could be that all the angles add up to 180

180-71= 109

∠DBC and ∠ABC must add up to 109 degrees

5 0
3 years ago
14-3(5t-12)=1-(20t+1)<br> How am I supposed to do this?
Nuetrik [128]
Expand by multiplying out:

14-15t + 36 = 1 -20t -1,
Because of the minus before the bracket, it changes the sign inside the bracket
-15t + 20t  = 1-1-14-36  Rearranging the ts on one side and the numbers on other
                                   side.
5t = -50  Divide both sides by 5.
t =  -50/5
t = -10.


5 0
3 years ago
Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(
Inessa05 [86]

Answer:

2+i

Step-by-step explanation:

Given the expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}

To find:

The expression of above complex number in standard form a+bi.

Solution:

First of all, learn the concept of i (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by i.

Value of i =\sqrt{-1}.

Now, let us consider the given expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i

So, the given expression in standard form is 2+i.

Let us compare with standard form a+bi so we get a =2, b =1.

\therefore The standard form of

\dfrac{4+\sqrt{16-(4)(5)}}{2}

is: \bold{2+i}

8 0
2 years ago
Quadratic Functions: Vertex Form
Keith_Richards [23]

Answer:

(5, -9).

Step-by-step explanation:

The vertex  if (h, k).

So for 6(x - 5)^2 - 9 the vertex is the point (5, -9).

7 0
3 years ago
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