Answer:
Area of bigger circle = 36.32cm²
Step-by-step explanation:
Kindly find attached rough sketch for your reference
This problem bothers on the mensuration of flat shapes, a circle
Kindly find attached
Given data
Area of small circle =9cm³
Say we assume the all unit is in cm
From the diagram we can see that the diameter of the small circle is the radius of the bigger circle
So let us solve for the diameter of the small circle
9= πr²
r²=9/3.142
r²= 2.86
r=√2.86
r= 1.7cm
But diameter of small circle
d= 2r
d= 1.7*2= 3.4cm
Hence the radius of the bigger circle is 3.4cm
Area of bigger circle =πr²
=3.142*3.4²
=3.142*11.56
Area of bigger circle = 36.32cm²
Answer:
1/16
Step-by-step explanation:
Substituting the given value of x into the equation, we get ...
You could round 77 to 80 and 65 to 70 and then add 70 and 80 and you will get 150
When it comes to laplace equations, there are transformation equations to follow. Generally, when you want to transform a laplace equation, you change the equation from f(t) to F(s). If you do the reverse, it is called the reverse laplace equation.
Based on the given, the useful transformation equation is shown in the attached picture.
When the term is s^2, that must mean that the equation is 1!/s^(1+1) to yield 1/s^2. This means that n=1. Taking the reciprocal s^2 must be equal to 1/t. Thus, for the first term, -11s^2 is equal to -11/t. For the second term, n must be equal to 6 so that 6!/s^(6+1) would yield 720/s^7. Thus, 720s^7 is equal to 1/t^6.
Hence, the transformed equation is
-11/t - 1/t^6
