Question 6 of 23 What is the slope-intercept equation of the line below?

What is the radius of the base of the cylinder 42in and 36 in

Usimov [2.4K]

Need additional information, which is the height and which is the diameter of the cylinder from the measurements supplied? Standard forumula for locating Radius and Volume of a cylinder are as follows.

Radius=Diameter/2
$rad=dia/2$

Volume=Base X height
$V=B*h$

Base= 3.14*r*r

8 0

3 years ago

Dayren is driving to visit family. She drives at a average of 65 miles per hour. She drives 227.5 miles before lunch. And then 9

Kitty [74]

Answer:

5 hours

Step-by-step explanation:

First, add the miles together

Next, divide 65 into the sum of 227.5 and 97.5(which is 325)

8 0

3 years ago

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Find the co-ordinate of the image of the point A (3, -2) when it is reflected on the line x=0 and then rotated about origin thro

Luba_88 [7]

Answer:

Step-by-step explanation:

Rotations are easy when its multiples of 90 degrees; 90,180,270,360. Treat them like they’re a complex number like [x+yi]*i=[-y,xi] so rotating by 90 degrees and 180 is i squared [-1]! So [-3,2] rot90 is [-2,-3].

Reflection about the y=x line is change places. [x.y]=[y,x].

So [-2.-3] reflected about the y=x line is [-2.-3]=[-3.-2],

Compile a list of these transform is best practice technique in this area.

5 0

3 years ago

A) {y=2x

sladkih [1.3K]

We can see that

both lines intersects at origin

so, the solution is x=0 and y=0

now, we will check each options

option-A:

$y=2x$

$y=-4x$

now, we can set them equal

and then we can solve for x

$-4x=2x$

$6x=0$

$x=0$

now, we can find y

$y=2*0$

$y=0$

so, solution is x=0 and y=0

so, this correct...........Answer

5 0

3 years ago

Find the Diameter of the Circle with the following equation. Round to the nearest tenth.

CaHeK987 [17]

Answer:

11.8 units

Step-by-step explanation:

The circle equation is given as:

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2Where

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2r

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we have

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35Take the square root of both sides

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35Take the square root of both sidesr = 5.9

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35Take the square root of both sidesr = 5.9Multiply by 2

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35Take the square root of both sidesr = 5.9Multiply by 22r = 11.8

The circle equation is given as:(x - 2)^2 + (y + 6)^2 = 35A circle equation is represented as:(x - a)^2 + (y - b)^2 = r^2WhereDiameter = 2rBy comparing both equations, we haver^2 = 35Take the square root of both sidesr = 5.9Multiply by 22r = 11.8Hence, the diameter of the circle is 11.8 units

8 0

1 year ago

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