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Alex17521 [72]
3 years ago
15

What number does y stand for in this equation?

Mathematics
1 answer:
mr_godi [17]3 years ago
7 0

Answer:

B. 21

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B%20x%20%2B%202%7D%20%20%3D%2012" id="TexFormula1" title="3 \sqrt[3]{ x +
joja [24]

Answer:dont know

Step-by-step explanation:

sorry

8 0
3 years ago
In April 2008, an audio CD was available for $14.01. the list price (full price) of the CD was $19.32. What was the percent disc
8_murik_8 [283]
19.30 - ( p / 100 )*19.32 = 14.01 ;
19.30( 1 - p/100 ) = 14.01 ;
1 - p/100 = 14.01 / 19.30
1 - p / 100 = 0.72 ;
p/100 = 1 - 72 / 100 ;
p/100 = 28 / 100 ;
p = 28 ;
The percent discount is 28% ;
4 0
3 years ago
Rapid rental car company charges a $40 rental fee $15 for gas, and $0.25 per mile driven. For the same car, Capital Cars charges
Elden [556K]
Sorry for taking so long.  Try typing in the whole question on google you will get lots of websites, it wasn't letting me post any here.

All the websites have $45 for the second sentence, but idk if they could help.

And when you figure it out let me know because it was really bothering me. lol

3 0
3 years ago
1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a
katovenus [111]

1. Let a and b be coefficients such that

\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}

Combining the fractions on the right gives

\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}

\implies 1 = (2a+b)x + 3a

\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23

so that

\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}

2. a. The given ODE is separable as

x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}

Using the result of part (1), integrating both sides gives

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C

Given that y = 1 when x = 1, we find

\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)

so the particular solution to the ODE is

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)

We can solve this explicitly for y :

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)

\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|

\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|

\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}

2. b. When x = 9, we get

y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}

8 0
2 years ago
6. Which is the BEST estimate of 2.4679+7.4939? A)O5.5
Goryan [66]

Answer:

A

Step-by-step explanation:

It because I think it is the correct

4 0
2 years ago
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