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Slav-nsk [51]
3 years ago
14

Which graph shows the solution set of

00" id="TexFormula1" title="\frac{x-1}{x-3} \ \textless \ 0" alt="\frac{x-1}{x-3} \ \textless \ 0" align="absmiddle" class="latex-formula">?

Mathematics
1 answer:
forsale [732]3 years ago
7 0

Answer:

Step-by-step explanation:

f(x) = (x - 1)/(x - 3) < 0

The critical points are x = 1 and x = 3

When x < 1, f(x) > 0

When 1 < x < 3,  f(x) < 0  

When x > 3,   f(x) > 0

Note  when x = 3 f(x) has no value and when x = 1 f(x) = 0.

I can't see all the graphs very well  but there should be a red line between 1 and 3 with a clear circle on x = 1 and x = 3.

Looks like its the last choice.

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I need help on this plz
balandron [24]

Answer:

(2) angle1 = 139, angle2 = 41, angle4 = 41, angle5 = 139, angle6 = 41, angle7 = 139, angle8 = 41

(3) angle1 = 150, angle2 = 30, angle4 = 30, angle5 = 150, angle6 = 30, angle7 = 150, angle8 = 30

Step-by-step explanation:

All angle are either equal to each other or supplementary.  I use corresponding angles and vertical angles to prove each of the above.

For number 3, angle 3 and angle 8 are supplementary, so they add up to 180:

8x +70 + (4x - 10) = 180

12x + 60 = 180

12x = 120

x = 10

So if x = 10, then 8x + 70 = 8(10) + 70 = 150

That means all angles are either 150 or 30 for number 3.

3 0
3 years ago
Can someone help me please?
ladessa [460]

Answer:

25/28 thats your answer

4 0
3 years ago
Read 2 more answers
a group of 50 people were asked their gender and if they liked cats. the data from the survey are shown in the ben diagram. dete
sasho [114]

Answer:

A=13, b= 28, c= 6 d=22 e=31

Step-by-step explanation:

E = 15 +16 = 31

6 males like cats ( the middle section) so C = 6

d = 6 +16 = 22

a = 19-6 = 13

b = 50-22 = 28

so in order: a = 13, b = 28, c = 6, d = 22, e = 31

6 0
3 years ago
A set of five integers contains 1 , 3 , and 22 . what other two integers must be included in this set so that the mean of all fi
d1i1m1o1n [39]
Total number of integers = 5

median
= (5+1)/2 th observation
= 3 rd observation

therefore the 3rd number = 13

now let the other number be x

total sum = 1+3+13+x+22 = 39+x

ATQ

(39+x)/5 = 16

39+x = 80

x = 41

the numbers are -

1,3,13,22,41
8 0
3 years ago
the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
3 years ago
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