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lutik1710 [3]
3 years ago
15

Find a.b. IaI =3, IbI = 5 the angle between a and b is 2π/3

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer: a\cdot b= -7.5

Step-by-step explanation:

Formula : If a and b be any two vector , then the dot product of and b is given by a\cdot b= |a||b|\cos {\theta} , where \theta is the angle between them.

As per given , we have

IaI =3, IbI = 5 \theta =\dfrac{2\pi}{3}

Then, a\cdot b= (3)(5)\cos \dfrac{2\pi}{3}

a\cdot b= (15)\cos ( \pi-\dfrac{\pi}{3})

a\cdot b= (15)(-\cos \dfrac{\pi}{3}) (∵ cos (π-x)=-cos x)

a\cdot b= (15)(-\dfrac{1}{2})  [∵\cos \dfrac{\pi}{3}=\dfrac{1}{2} ]

a\cdot b= -7.5

Therefore , a\cdot b= -7.5

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