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ra1l [238]
3 years ago
8

The absolute value |x-3|<1

Mathematics
2 answers:
choli [55]3 years ago
5 0
|x-3| < 1

make it to the possible solution

x-3 < 1 -------> (1)

-(x-3) < 1 ------> (2)


in equation (1)

x<1+3
x < 4

in equation (2)

-x + 3 < 1

-x < 1-3

-x < -2

x > 2

x ∈ (2,4)
zhenek [66]3 years ago
4 0

Answer:

in kiloliters its 0.0035

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A rectangular prism measures 225 inches by 315 inches by 2 inches. How many cubes with edge length 15 inch fit in the prism? Sho
Mandarinka [93]

Answer:

34 Cubes

Step-by-step explanation:

<u>Step 1: </u>Find the Volume of the Rectangular Prism

The dimensions of the rectangular prism are: 225 inches by 315 inches by 2 inches.

Volume of the Rectangular Prism = 225*315*2=141750 Cubic Inches

<u>Step 2:</u> Find the Volume of the Cube

Edge length of the cube, s=15 Inch

Volume of a Cube =s^3

Volume=15^3=3375 Cubic Inches

<u>Step 3: </u>Determine how many cubes fit in the prism

To find out how many cubes fit in the rectangular prism, divide the volume of the rectangular prism by the volume of the cube.

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=141750 ÷ 3375

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34 Cubes will fit in the rectangular prism.

6 0
3 years ago
Jonah earns $12.50 per hour as a marketing intern. If he works for 4.5 hours,how many dollars does he earn?
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5 0
3 years ago
One positive integer is 3 greater than 4 times another positive integer. If the product of the two integers is 76, then what is
andrew11 [14]

Answer:

The sum of the two integers is 23

Step-by-step explanation:

Let one integer be x and the other integer be y

Then according to the statement "One positive integer is 3 greater than 4 times another positive integer.."

x be the integer that is One positive integer is 3 greater than 4 times another positive integer.

Then

x= 3+4y----------------------------------(1)

Product of the two integer is 76, this can  written as

x \times y =76

substituting the values of x from eq(1)

( 3+4y) \times y =76

3y + 4y^2 = 76

3y + 4y^2-76= 0

4y^2 + 3y -76= 0

Solving the quadratic equation equation we get

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

here

a = 4

b= 3

c = -76

susbtituting the above values in the formula

y=\frac{-3 \pm \sqrt{3^2-4(4)(-76)}}{2(4)}

y=\frac{-3 \pm \sqrt{9- 4(4)(-76)}}{8}

y=\frac{-3 \pm \sqrt{9- (16)(-76)}}{8}

y=\frac{-3 \pm \sqrt{9- (-1216)}}{8}

y=\frac{-3 \pm \sqrt{9 + 1216}}{8}

y=\frac{-3 \pm \sqrt{1225}}{8}

y=\frac{-3 \pm 35}{8}

y=\frac{-3 +35}{8}                       y=\frac{-3 -35}{8}    

y=\frac{32}{8}                             y=\frac{-38}{8}

y= 4                                                           y =  −4.75

Since in the  question it is given that it is a positive integer

so  y = 4

substituting y=4 in eq (1) we get,

x= 3+4(4)

x= 3+16

x= 19

The sum of the two integers

=> x + y

=> 19+4

=>23

8 0
4 years ago
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