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Novosadov [1.4K]
3 years ago
15

1.Two cyclists are 7 miles apart when they begin biking away from each other in opposite directions. The speed of the first cycl

ist is 12 miles per hour. The speed of the second cyclist is b miles per hour greater than the speed of the first cyclist.
How many miles does the first cyclist bike in 45 minutes?
Mathematics
2 answers:
charle [14.2K]3 years ago
5 0

Answer:

25+3b/4

Step-by-step explanation:

9+7 because 9 is how many miles the first guy biked in 45 minutes and the 7 is how many miles apart they were in the first place.

9+7+9+3b/4

There is ur answer

Nastasia [14]3 years ago
4 0

Answer:

9 miles

Step-by-step explanation:

If 1 hour is 12 miles, then 30 mins is 6 miles, then 15 minutes is 3 miles.

30+15=45

6+3=9

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3 0
4 years ago
Air-USA has a policy of booking as many as 24 persons on an airplane that can seat only 22. (Past studies have revealed that onl
Alex17521 [72]

Answer:

B. no, it is not low enough

A. no, it is not low enough

Step-by-step explanation:

Given that Air-USA has a policy of booking as many as 24 persons on an airplane that can seat only 22.

Prob for  a random person booked arrive for flight = 0.86

No of persons who books and arrive for flight, X is binomial, since there are two outcomes and each person is independent of the other

The probability that if Air-USA books 24 persons, not enough seats will be available

= P(X=23)+P(x=24)

= 0.1315

B. no, it is not low enough

-------------------------------

The prob we got is >10% also

A. no, it is not low enough

7 0
3 years ago
How do you find answer for 8k=4/9
nasty-shy [4]
Isolate k by dividing both sides by 8

8k=4/9
k=4/72

Reduce if possible

4/72 -> 1/18
8 0
4 years ago
Read 2 more answers
At a certain high school, 15 students play stringed instruments and
Aleks [24]

Answer:

<em>0</em> is the probability that a  randomly selected student plays both a stringed and a brass  instrument.

Step-by-step explanation:

Given that:

Number of students who play stringed instruments, N(A) = 15

Number of students who play brass instruments, N(B) = 20

Number of students who play neither, N(A \cup B)' = 5

<u>To find:</u>

The probability that a randomly selected students plays both = ?

<u>Solution:</u>

Total Number of students = N(A)+N(B)+N(A \cup B)' =15 + 20 + 5 = 40

(As there is no student common in both the instruments we can simply add the three values to find the total number of students)

As per the venn diagram, no student plays both the instruments i.e.

N(A\cap B) =0

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A\cap B) = \dfrac{N(A\cap B)}{N(U)}\\\Rightarrow \dfrac{0}{40}\\\Rightarrow P(A\cap B) = 0

So, <em>0</em> is the probability that a  randomly selected student plays both a stringed and a brass  instrument.

5 0
3 years ago
Gabriel buys 5 pounds of apples for $8. Allie buys 10 pounds of the same apples for $16. Which of the following points is NOT on
Tom [10]
I don't understand your question
4 0
4 years ago
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