1.f
2.c
3.b
4.e
5.a
6.d
in order
Answer:
B. no, it is not low enough
A. no, it is not low enough
Step-by-step explanation:
Given that Air-USA has a policy of booking as many as 24 persons on an airplane that can seat only 22.
Prob for a random person booked arrive for flight = 0.86
No of persons who books and arrive for flight, X is binomial, since there are two outcomes and each person is independent of the other
The probability that if Air-USA books 24 persons, not enough seats will be available
= P(X=23)+P(x=24)
= 0.1315
B. no, it is not low enough
-------------------------------
The prob we got is >10% also
A. no, it is not low enough
Isolate k by dividing both sides by 8
8k=4/9
k=4/72
Reduce if possible
4/72 -> 1/18
Answer:
<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
Step-by-step explanation:
Given that:
Number of students who play stringed instruments, N(A) = 15
Number of students who play brass instruments, N(B) = 20
Number of students who play neither, N(
)' = 5
<u>To find:</u>
The probability that a randomly selected students plays both = ?
<u>Solution:</u>
Total Number of students = N(A)+N(B)+N(
)' =15 + 20 + 5 = 40
(As there is no student common in both the instruments we can simply add the three values to find the total number of students)
As per the venn diagram, no student plays both the instruments i.e.

Formula for probability of an event E can be observed as:


So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.