All categories

3 years ago

What is the relationship between CE and AD? I’ll give brainly

Mathematics

1 answer:

Step2247 [10]3 years ago

4 0

It’s the second one because it can’t be half but it can be 1/4 and if you do the measurements you can tell it is the second one

You might be interested in

Sally has a discount card that reduces the price of her grocery bill in a certain grocery store by 5%. If c represents the cost

amm1812

The original price is c. Then the grocery bill will be: c - 0.05c = 0.95 c. You can also say since the beggining that 5% disscount implies 0.95 factor, which leads to c * 0.95 = 0.95c. Sorry if it’s wrong

3 0

3 years ago

In AGHI, the measure of ZI=90°, the measure of ZG=5°, and IG = 57 feet. Find the

xxTIMURxx [149]

Answer:

The answer is 57.2

This is correct

3 0

3 years ago

Which channel is the most popular one for the evening news

makvit [3.9K]

WANR: 22%
WWCN: 41%
WCLM: 24%
WKOD: 13%

However is B. WWCN.

7 0

3 years ago

Read 2 more answers

Please answer the following questions

laila [671]

Answer:

4a) 110 square centimetres

4b) 127 square centimetres

6) 292 square centimetres

8) 800 tiles

Step-by-step explanation:

4. We need to find the area of the large rectangle and then deduct the area of the unshaded part:

a) The large rectangle has dimensions 12 cm by 15 cm. Its area is:

A = 12 * 15 = 180 square centimetres

The unshaded part has a length of 15 - (3 + 2) cm i.e. 10 cm and a width of 7 cm. Its area is:

a = 10 * 7 = 70 square centimetres

Therefore, the area of the shaded part is:

A - a = 180 - 70 = 110 square centimetres

b) The large rectangle has dimensions 13 cm by 11 cm. Its area is:

A = 13 * 11 = 143 square centimetres

The unshaded part has dimensions 8 cm by 2 cm. Its area is:

a = 8 * 2 = 16 square centimetres

Therefore, the area of the shaded part is:

A - a = 143 - 16 = 127 square centimetres

6. The background area of the space not covered by the photograph is the area of the frame minus the area of the photograph.

The frame has dimensions 24 cm by 18 cm. Therefore, its area is:

A = 24 * 18 = 432 square centimetres

The photograph has dimensions 14 cm by 10 cm. Therefore, its area is:

a = 14 * 10 = 140 square centimetres

Therefore, the background area of the space not covered by the photograph is:

A - a = 432 - 140 = 292 square centimetres

8) The floor has dimensions 8 m by 4 m. The area of the floor is:

A = 8 * 4 = 32 square centimetres

Each square tile has dimensions 20 cm by 20 cm. In metres, that is 0.2 m by 0.2 m. The area of each tile is:

a = 0.2 * 0.2 = 0.04 square metres

The number of tiles that are needed is the area of the floor divided by the area of each tile:

A / a = 32 / 0.04 = 800 tiles

4 0

4 years ago

A farmer builds a fence to enclose a rectangular pasture.He uses 155 feet of fence. Find the total area of the pasture if it is

ICE Princess25 [194]

The area for the perimeter of a rectangle is:
<em>P = 2l + 2w</em>
In this problem, we are given that P = 155 and l = 45.5. To solve for area, we must find w. To do this, plug in the given info and isolate the w like so:
$155=2(45.5)+2w \\ 155=91+2w \\ (155)-91=(91+2w)-91 \\ 64=2w \\ \frac{64}{2} = \frac{2w}{2} \\ w=32$
Now we know w = 32. Knowing all the necessary info, we can use the area formula, <em>A=lw</em>, to solve for A.
$A=(45.5)(35) \\ A=1,456$

The area is 1,456 sq ft.

Hope this helps!

5 0

4 years ago