Answer:
For
the function f(x) is continuous on
.
Step-by-step explanation:
We have the following function

For the function f(x) to be continuous on
it is sufficient to have continuity at x = 6, we need to ensure that as x approaches 6, the left and right limits match, this means that
,
which holds if and only if

namely if
.
Step-by-step explanation:
6m+5-3m=7(m-1)
3m+5=7m-1
5+1=7m-3m
6=4m
6/4=m
3/2=m
I think it is correct .
We have been given that the inverse variation
shows the relationship between wavelength in meters, x, and frequency, y. We are asked to find the wavelength for radio waves with frequency
.
To find the required wavelength, we substitute
in our given equation and solve for x as:


We can see that both numerator and denominator has 3, so we can cancel it out.

Using quotient rule of exponents
, we will get:


Therefore, the wavelength for radio waves would be
meters and option B is the correct choice.
What nanajdisn at x Andorrans
Answer:
\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]
Step-by-step explanation:
Given is a matrix 3x3 as
![\left[\begin{array}{ccc}1&0&2\\-3&1&4\\2&-3&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%262%5C%5C-3%261%264%5C%5C2%26-3%264%5Cend%7Barray%7D%5Cright%5D)
|A| =2 hence inverse exists.
Cofactors are 16 20 7
6 8 3
2 2 1
Hence inverse =
![\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%266%262%5C%5C20%268%262%5C%5C7%263%261%5Cend%7Barray%7D%5Cright%5D)