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3 years ago

48% de 8,4===============

Mathematics

1 answer:

Fofino [41]3 years ago

3 0

Answer: 4,032

Step-by-step explanation:

8,4 x 0,48 = 4,032

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Correct answers only please!!

Burka [1]

Answer:

Step-by-step explanation:

The distance between points A and B is 7.

Have a great day! :)

and can I please have brainliest?

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3 years ago

Sally is buying new school supplies she uses a 15% off coupon on the set of markers that was originally $3 she also bought some

timurjin [86]

[(100-15)/100 * $3]
= $2.55
$5.35 - $2.55
= $2.80 |80% paper|

80/100 = 2.80/x
4/5 = 2.80/x
4x = 14
x = 3.5

Original price of the paper = $3.50

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3 years ago

Lea and Marie are washing all the windows in their house. It would take Lea 80 minutes to wash the windows by herself, and it wo

valentina_108 [34]

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3 years ago

Read 2 more answers

Find the value of 5w+1 given that 7w-7=7.

Katyanochek1 [597]

Answer:

lets find the exact value of w

7w - 7 = 7

+7 +7

7w = 14

/7 /7

w = 2

Now let's replace w with 2

5(2) + 1 = 11

4 0

2 years ago

5. The superintendent of the local school district claims that the children in her district are brighter, on average, than the g

anygoal [31]

Answer:

We conclude that children in district are brighter, on average, than the general population.

Step-by-step explanation:

We are given the following data set:

105, 109, 115, 112, 124, 115, 103, 110, 125, 99

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1117}{10} = 111.7$

Sum of squares of differences = 642.1

$S.D = \sqrt{\frac{642.1}{49}} = 8.44$

We are given the following in the question:

Population mean, μ = 106

Sample mean, $\bar{x}$ = 111.7

Sample size, n = 10

Alpha, α = 0.05

Sample standard deviation, s = 8.44

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 106\\H_A: \mu > 106$

We use one-tailed(right) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{111.7 - 106}{\frac{8.44}{\sqrt{10}} } = 2.135$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = 1.833$

Since,

$t_{stat} > t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that children in district are brighter, on average, than the general population.

4 0

2 years ago

48% de 8,4===============​

48% de 8,4===============