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ANEK [815]
4 years ago
6

Evaluate 39÷(2+1)-2×(4+1)

Mathematics
1 answer:
Arada [10]4 years ago
5 0
I believe the answer is 3. Order of Operations is Parenthesis Exponents Multiplication and Division solve left to right and Addition and Subtraction solve left to right
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Need help asap<br> 8th grade math
Firdavs [7]

Answer:

x = 0

Step-by-step explanation:

The distributive property of multiplication states that a(b - c) = a(b) - a(c). We can apply that to the given equation.

3(2 - x) = 6

3(2) - 3(x) = 6 (Apply distributive property on LHS)

6 - 3x = 6 (Simplify LHS)

6 - 6 - 3x = 6 - 6 (Subtract 6 from both sides)

-3x = 0 (Simplify both sides)

\frac{-3x}{-3} =\frac{0}{-3} (Divide both sides by -3)

x = 0 (Simplify)

Hope this helps!

8 0
4 years ago
Which of the following is the quotient of the rational expressions shown here? x/x-1 / 1/x+1.
grandymaker [24]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
Which is the equation of a line whose slope is -2 and whose y-intercept is 3?
marusya05 [52]

Answer:

y = -2x + 3

Step-by-step explanation:

The slope-intercept formula for a line is y = mx + b where m is the slope and b is the y intercept. Therefore, just sub -2 for m and 3 for b.

5 0
3 years ago
Does anyone know this?? Pls help!
kozerog [31]

Answer: x^3 -12x^2+31x-96+ 292/x+3

The remainder is 292

Step-by-step explanation: I used synthetic division to get the answer and got the answer above. I hope this helped :)

8 0
3 years ago
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Which of the functions graphed below has a removable discontinuity?<br> A<br> B<br> C<br> D
PtichkaEL [24]
<h2>Answer with explanation:</h2>

We know that a removable discontinuity occurs when:

The left and the right hand limit of the function exist at a point and are equal but is unequal to the function's value at that point.

Also it is a  point on the graph such that it is undefined at that point.

The graph that has a removable discontinuity is attached to the answer.

Since, at x=0 the left hand and the right hand limit of the function exist but the function is not defined at x=0 , since in the graph there is a open circle at x=0 that means that the point is removed from the range.

5 0
3 years ago
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