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3 years ago

Hello world can you help me with math?

Mathematics

1 answer:

Leno4ka [110]3 years ago

8 0

Answer:

Im going to have to say C

Step-by-step explanation:

I hope this helps you out!

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CAN SOMEONE PLS ANSWER-If W(- 10, 4), X(- 3, - 1) , and Y(- 5, 11) classify AEXY by its sides . Show all work to justify your an

AnnZ [28]

Answer:

WX = $\sqrt{74} \approx 8.6023253\\\\$
XY = $2\sqrt{37} \approx 12.1655251\\\\$
WY = $\sqrt{74} \approx 8.6023253\\\\$
Classify: Isosceles

============================================================

Explanation:

Apply the distance formula to find the length of segment WX

W = (x1,y1) = (-10,4)

X = (x2,y2) = (-3, -1)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-3))^2 + (4-(-1))^2}\\\\d = \sqrt{(-10+3)^2 + (4+1)^2}\\\\d = \sqrt{(-7)^2 + (5)^2}\\\\d = \sqrt{49 + 25}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\$

Segment WX is exactly $\sqrt{74}$ units long which approximates to roughly 8.6023253

-------------------

Now let's find the length of segment XY

X = (x1,y1) = (-3, -1)

Y = (x2,y2) = (-5, 11)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-3-(-5))^2 + (-1-11)^2}\\\\d = \sqrt{(-3+5)^2 + (-1-11)^2}\\\\d = \sqrt{(2)^2 + (-12)^2}\\\\d = \sqrt{4 + 144}\\\\d = \sqrt{148}\\\\d = \sqrt{4*37}\\\\d = \sqrt{4}*\sqrt{37}\\\\d = 2\sqrt{37}\\\\d \approx 12.1655251\\\\$

Segment XY is exactly $2\sqrt{37}$ units long which approximates to 12.1655251

-------------------

Lastly, let's find the length of segment WY

W = (x1,y1) = (-10,4)

Y = (x2,y2) = (-5, 11)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-5))^2 + (4-11)^2}\\\\d = \sqrt{(-10+5)^2 + (4-11)^2}\\\\d = \sqrt{(-5)^2 + (-7)^2}\\\\d = \sqrt{25 + 49}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\$

We see that segment WY is the same length as WX.

Because we have exactly two sides of the same length, this means triangle WXY is isosceles.

8 0

3 years ago

35 hundreds=5 tens×7 tens is this true or false

nikdorinn [45]

False cause i said so

6 0

4 years ago

C+ax=dx this one has all variables and no numbers

sergeinik [125]

That's OK, but you have not said which variable you want to solve it for.

To solve for 'x':
 c + ax = dx

Subtract c from each side: ax = dx - c

Subtract dx from each side: ax - dx = -c

Factor the left side: x (a - d) = -c

Divide each side by (a - d) : x = -c / (a - d) or x = c / (d - a) .

To solve for 'c': 
 c + ax = dx

Subtract ax from each side and factor: c = x (d - a) 

To solve for 'd': 
 c + ax = dx

Divide each side by 'x': d = c/x + a .

To solve for 'a':
 c + ax = dx

Subtract 'c' from each side: ax = dx - c

Divide each side by 'x': a = d - c/x .
.

6 0

3 years ago

GIVING BRAINLIEST!!!!!! 32+4X(16 x 1/2)-2 show your work

Yuliya22 [10]

Answer:

32x + 30

Step-by-step explanation:

32+4X(16 x 1/2)-2

32 + 4X x 8 -2 ( 16 times 1/2 = 8)

32 + 32x -2 ( 4 times 8 = 32)

32x + 30 ( 32 + -2 = 30)

20+(5 * 2/5)+3

20 + 2 + 3

22 + 3

4 0

3 years ago

Solve each system by substitution x - y=4 x+2y=-2

DENIUS [597]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}x-y=4&\text{add}\ y\ \text{to both sides}\\x+2y=-2\end{array}\right\\\\\left\{\begin{array}{ccc}x=4+y&(1)\\x+2y=-2&(2)\end{array}\right\\\\\text{substitute (1) to (2):}\\\\(4+y)+2y=-2\qquad\text{combine like terms}\\\\4+(y+2y)=-2\qquad\text{subtract 4 from both sides}\\\\3y=-6\qquad\text{divide both sides by 3}\\\\y=-2\\\\\text{put the value of}\ y\ \text{to (1):}\\\\x=4+(-2)\\\\x=2$

7 0

3 years ago