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belka [17]
3 years ago
5

How to find the equation of a parabola given the vertex and one point?

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0
First, write down y=a(x-the x coordinate of the vertex)^2+the y coordinate of the vertex)
second, plug the x coordinate and coordinate of the given point in the above equation to find out a
For example, vertex is (1,2), the point is (3,4)
y=a(x-1)^2+2 
then plug in x=3, y=4 in the above equation to find out a
4=a(3-1)^2+2
4=4a+2
4a=2
a=1/2
the equation of the parabola with a vertex at (1,2) and passes through the point (3,4) is 0.5(x-1)^2+2
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1. 200

2. 0.05

3. Please find attached the graph of the exponential function and the table

\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}

4. Range; [0, ∞)

Domain: [200, ∞)

5. 346 fishes (approximate value)

<h3>How is the population of the fish obtained from the exponential function?</h3>

The given function is f(x) = 200·(1.05)ˣ

1. The initial population is given by the value of the function when x = 0,

which is given as follows;

At x = 0, f(0) = 200·(1.05)⁰ = 200

  • The initial population of the fish is <u>200</u>

2. The rate of growth of the fish from the exponential function is given as follows;

The growth factor = 1.05

  • The growth rate =<u> 0.05</u>

3. Please find attached the graph of the exponential function created

with MS Excel.

The asymptote of the exponential function is the line, <u>y = 0</u>

The table of values is presented as follows;

\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}

4. The domain is the possible x-values which is; 0 ≤ x < ∞

The range is the possible y-values which is; 200 ≤ f(x) < ∞

Which gives;

  • Domain; [0, ∞)
  • Range: [200, ∞)

5. The population of the fish after 11 years is f(11) = 200·(1.05)¹¹

f(11) = 200 × (1.05)¹¹ ≈ 342

  • The population of the fish after 11 years is <u>346 (fishes)</u>

Learn more about exponential function here:

brainly.com/question/15662160

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