Answer:
x=7
Explanation:
-3 1/4x+25= 2 1/4x-13 1/2
25=5 1/2x-13 1/2
38 1/2=5 1/2x
7=x
Answer:
56 and there will be 1 foot of ribbon left over
Step-by-step explanation:
225/4=56.25
The number of students would not change between before the test and after the test. 3+8 and 4+7 both = 11 so finding out how many students would equal one ratio can then be used to find how many equal 3 and 8.
If 92 students are equal to 4 in the ratio, then 1 in the ratio is worth 23 students. This is important as then when you times 23 by 7 you find out how many students there are in the regular maths class, 161 students. Plussing these two together gives you a total of 253 students.
Using this 253 you can divide it by 11 to find out how much 1 number would be in the ratio, it equals 23. Using this you can then times 23 by both 3 and 8 to find the original class sizes, 3x23 = 69, and 23x8 = 184.
Making the origional class size of the advaced class 69 studnets, and the regular maths class size 184.
Answer:
<em> SSS</em><em> can be used to prove that the given triangles are congruent.</em>
Step-by-step explanation:
In the given two triangles ΔADC and ΔABC,
- AD = AB = 7 units,
- CD = BC = 8 units,
- AC is common to both triangles,
Hence, ΔADC ≅ ΔABC by Side-Side-Side (SSS) congruence.
SSS congruence-
If three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.
