Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26
For this case we have to:

Where:
a: It's the Dividend
b: It is the Divider
c: Is the Quotient
Thus, the expression "the quotient of 5 and x" can be represented as:

Where "y" is the quotient of 5 and x.
ANswer:

Area=l*b=l*(l-2)=80(given)
so, l^2 - 2l =80
l^2 - 2l - 80=0
l=10 or -8
l=10,b=10-2=8
perimeter=2(l+b)=2(18)=36
You can use any numbers for the Y you figure out you points. :)
Answer: 4
Step-by-step explanation: