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3 years ago

Find the fractional part the first number is of the second examples:12;30,9;27,15;50

Mathematics

1 answer:

marin [14]3 years ago

6 0

Answer:

a) 2/5

b) 1/3

c) 3/10

Step-by-step explanation:

a)12;30

= 12/30

= 2/5

b)9;27

= 9/27

= 1/3

c) 15;50

= 15/50

= 3/10

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Find the smallest value of k such that the LCM of k and 6 is 60

Advocard [28]

Answer: The smallest valuest value for k is 10, such that LCM of k and 6 is 60.

Step-by-step explanation:

We know that, LCM = Least common multiple.

For example : LACM of 12 and 60 is 60.

If LCM of k and 6 is 60.

i.e. the least common multiple of k and 6 is 60.

Since, 10 x 6 = 60.

The smallest valuest value for k should be 10, such that LCM of k and 6 is 60.

Hence, the smallest value of k is 10.

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3 years ago

Solve for area of the shaded region (#61) Pls explain im so confused

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Step-by-step explanation:

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3 years ago

If the tank is then field to capacity how many half-gallon bottles how many cords will it make?

lukranit [14]

Answer:

Divide 12 by 4 first to figure out how many gallons are in each 1/4 of the tank.

12/4=3

So if I added another 1/4 to the capacity:

It could hold 15 gallons.

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3 years ago

What is the probability a sample of 90 test takers will provide a sample mean test score within 10 points of the population mean

Elena-2011 [213]

Answer:

0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

Step-by-step explanation:

The following information is missing:

The standard deviation of population is 100.

We are given the following information in the question:

Population mean, μ = 502

Standard Deviation, σ = 100

Sample size, n = 90

Standard error =

$\dfrac{\sigma}{\sqrt{n}} = \dfrac{100}{\sqrt{90}} = 10.54$

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(test score within 10 points)

$P(492 \leq x \leq 512) \\\\= P(\displaystyle\frac{492 - 502}{10.54} \leq z \leq \displaystyle\frac{512-502}{10.54}) \\\\= P(-0.9487 \leq z \leq 0.9487)\\= P(z \leq 0.9487) - P(z < -0.9487)\\= 0.829 -0.171 = 0.658 = 65.8\%$

$P(492 \leq x \leq 512) = 65.8\%$

0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

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3 years ago