All categories

2 years ago

PLEASE PLEASE PLEASEE HELP LAST TIME I ANSWERED NOBODY ANSWER PLS HALP

Mathematics

1 answer:

Sophie [7]2 years ago

8 0

Answer:

He is correct because the key term is "greater than". This indicates that inequalities should be used here. Now, we write the inequality.

Explanation:

Let L = length

Let w = width

Perimeter = 2L + 2w

L = 100

Perimeter > 400

2(100) + 2w > 400

200 + 2w > 400 is the inequality

Subtract 200 on both sides of inequality.

2w > 200

w > 100

The width is at least 100 centimeters.

You might be interested in

Plz help worth 50 points

serious [3.7K]

Answer:

The answer is A

Step-by-step explanation:

Starting from -3 in the Y values of option A. If you subtract three from each value, you will get the next value to the right.

-3 minus -3 = -6
-6 minus -6 = -9

6 0

3 years ago

Read 2 more answers

Help please:) i’m trying to get all of this work completed but i just don’t understand it

leva [86]

$\pi r^{2} =\\3,14*4^{2} \\3,14*16\\=50.24$

8 0

2 years ago

Read 2 more answers

The graph shows the data of texting speed according to time.

hichkok12 [17]

The answer is B on edgeunity

3 0

2 years ago

Read 2 more answers

Convert the fraction 3/11 to a decimal using long division

Dvinal [7]

0.27

so three divided by eleven is 0.27272727272727272727272727272727........so on and so forth.

7 0

3 years ago

Nadia plans to paint her jewelry box. The box is shaped like a rectangular prism with the dimensions

Pachacha [2.7K]

Answer:

$132\ in^{2}$ is closest to the total surface area of the box

Step-by-step explanation:

we know that

The surface area of the box is equal to

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the box

we have

$L=7\frac{3}{4}\ in=\frac{7*4+3}{4}=\frac{31}{4}\ in$

$W=3\frac{1}{4}\ in=\frac{3*4+1}{4}=\frac{13}{4}\ in$

$H=3\frac{7}{8}\ in=\frac{3*8+7}{8}=\frac{31}{8}\ in$

Find the area of the base B

$B=LW$

$B=(\frac{31}{4})(\frac{13}{4})=\frac{403}{16}\ in^{2}$

Find the perimeter of the base P

$P=2(L+W)$

$P=2(\frac{31}{4}+\frac{13}{4}))$

$P=2(\frac{44}{4})=22\ in$

Find the surface area

$SA=2(\frac{403}{16})+22(\frac{31}{8})$

$SA=(\frac{403}{8})+(\frac{682}{8})$

$SA=\frac{1,085}{8}=135.625\ in^{2}$

6 0

3 years ago