Given that t<span>riangle QST is isosceles, and bisects T, the line bisecting T also bisects QS.
A line that bisects the other angle of an isosceles triangle,</span> bisects the opposite line at right angle. Therefore, since triangle <span>QST is isosceles, and bisects T, the line bisecting T bisects QS at R and then QRT = SRT = 90 degrees.
QRT cannot be equal to STQ since an isosceles triangle does not have a right angle as QRT is a right angle.
2*RTQ is equivalent to STQ, and it has been established that QRT is not equal to STQ. Thus QRT is not equal to 2*RTQ.
QRT </span><span>cannot be equal to RTQ since an isosceles triangle does not have a right angle as QRT is a right angle.
Therefore, the true statements about QRT is QRT = SRT.</span>
Answer:
Step-by-step explanation:
f(x) = ax+b
passing through the point (6,-1) : when x = 6 f(x) = -1
means : -1 = a (6)+b
passing through the point (-3,-2) : when x = -3 f(x) = -2
means : --2 = a (-3)+b
you have the system :: 6a +b = - 1......(1)
-3a +b = -2........(2)
by (1) : b = -1 - 6a
by (2) : b = -2+3a
so : -2+3a = -1 - 6a
3a+6a =2 -1
9a =1 a =1/9 put the value of a in (1) or (2) : -3(1/9)+b = - 2
-1/3 +b = - 2
b = -2+1/3
b = -5/3
f(x) = 1/9 x - 5/3