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3 years ago

The circumference of a circular design is 2020 inches.

Mathematics

2 answers:

zhuklara [117]3 years ago

5 0

Answer:

Diameter of the circle is twice it's radius D=2r.

Circumference of the circle is 2πr.

According to the above problem,

2π(radius)=20 inches

2(radius)=20/π=20/3.14

Diameter=6.37 inches

<h3>6.37 inches is the right answer.</h3>

musickatia [10]3 years ago

4 0

The answer is 6.37 your welcome

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3 years ago

Find two numbers whose product is -2, and whose sum is -1.

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$x=-2 \ \ \ and \ \ \ y=1$

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2 years ago

After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i

Crazy boy [7]

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The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume ( $V$ ) is calculated by:

$V = \frac{4\pi}{3}\cdot R^{3}$

Where $R$ is the radius of the tumor.

The percentage decrease in the volume of the tumor ( $\%V$ ) is expressed by:

$\%V = \frac{\Delta V}{V_{o}} \times 100\,\%$

Where:

$\Delta V$ - Absolute decrease in the volume of the tumor.

$V_{o}$ - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

$\Delta V = V_{o}-V_{f}$

$\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})$

The percentage decrease is finally simplified:

$\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%$

Given that $R_{o} = R$ and $R_{f} = 0.77\cdot R$ , the percentage decrease in the volume of tumor is:

$\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%$

$\%V = 54.34\,\%$

The volume of the tumor experimented a decrease of 54.34 percent.

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3 years ago