To dilate an object means to enlarge or reduce the size of the object. The scale factor will determine how much larger or smaller the object will become. If this factor is greater than 1, the object will increase in size. Otherwise, if the factor is less than 1, the object will decrease in size. So, the dilated object will be similar to its original. On the other hand, when corresponding points of the original and dilated figures are connected by straight lines, the center of dilation is the point where all the lines meet. In this problem, the center is (0, 0). When the center is the origin we need to multiply all the original coordinates of the object by the scale factor given. So:
![A(-4, 1) \rightarrow A'=-2(-4,1) \rightarrow A'(8,-2) \\ \\ B(-3, -4) \rightarrow B'=-2(-3,-4) \rightarrow B'(6,8) \\ \\ C(-2, -2) \rightarrow C'=-2(-2,-2) \rightarrow C'(4,4)](https://tex.z-dn.net/?f=%20A%28-4%2C%201%29%20%5Crightarrow%20A%27%3D-2%28-4%2C1%29%20%5Crightarrow%20A%27%288%2C-2%29%20%5C%5C%20%5C%5C%20B%28-3%2C%20-4%29%20%5Crightarrow%20B%27%3D-2%28-3%2C-4%29%20%5Crightarrow%20B%27%286%2C8%29%20%5C%5C%20%5C%5C%20C%28-2%2C%20-2%29%20%5Crightarrow%20C%27%3D-2%28-2%2C-2%29%20%5Crightarrow%20C%27%284%2C4%29%20)
So, the graph of the dilated triangle is shown in the Figure below
This is the concept algebra.
Volume of of paint that is required to paint large shipping crate is a liters.
suppose the volume of this crate is x cubic units.
The volume of the next crate to be painted will be 2x cubic units.
Hence the amount of paint required to paint the crate will be:
(volume of bigger crate)/(volume of smaller crate)×(volume of liters required to paint the first crate)
=(2x)/(x)×a
=2a liters
To paint the new crate 2a liters of oil is needed.
Answer:
21.6
Step-by-step explanation:
i did the math
Step-by-step explanation:
![{x}^{2} + 14x + 24 = 0 \\ {x}^{2} + 12x + 2x + 24 = 0 \\ x(x + 12) + 2(x + 12) = 0 \\ (x + 12)(x + 2) = 0\\ x = - 12 \\ x = - 2](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%2014x%20%2B%2024%20%3D%200%20%5C%5C%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%2012x%20%2B%202x%20%2B%2024%20%3D%200%20%5C%5C%20x%28x%20%2B%2012%29%20%2B%202%28x%20%2B%2012%29%20%3D%200%20%5C%5C%20%28x%20%2B%2012%29%28x%20%2B%202%29%20%20%3D%200%5C%5C%20x%20%3D%20%20-%2012%20%5C%5C%20x%20%3D%20%20-%202)
Let's let the weight of a large box be L, and the weight of a small box be S.
We know that 5 large boxes and 3 small boxes is 120kg, so:
5L + 3S = 120
We also know that 7 large boxes and 9 small boxes is 234kg, so:
7L + 9S = 234
You can multiply the first equation by 3 to get:
15L + 9S = 360
See how now both equations have 9S? We can now subtract one from the other:
(15L+9S) - (7L+9S) = 360-234
8L = 126
L = 15.75
Now sub this value back into an equation:
(5x15.75) + 3S = 120
3S = 41.25
S = 13.75
Double check these values
(7x15.75) + (9x13.75)
= 110.25 + 123.75
=234, which is consistent with above.
So a large box is 15.75kg, and a small box is 13.75kg.
Hope this helped