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3 years ago

Simplify square root of 10 multiply by square root of 8

Mathematics

2 answers:

Tju [1.3M]3 years ago

5 0

Answer:

I believe the answer you're looking for is 3.16227766 x 2.828427125=

If that's not what you looking for the answer to square root of 10 times square root of 8 equals 8.94427191

Ivan3 years ago

3 0

Answer:

4squareroot5

Step-by-step explanation:

<em>hope this helps. i am in algebra two so you can trust my answer. happy holidays and stay safe!</em>

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Mr Langley sold all but 10 of his old computers for R500 each . He received R32 500 from the sale .How many computers did he ori

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Answer:

75 computers

Step-by-step explanation:

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65 +10= 75 computers originally

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3 years ago

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Step-by-step explanation:

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3 years ago

From the set (76, 77, 78), use substitution to determine which value of x makes the equation true

jeyben [28]

Answer:

The answer is C.

Step-by-step explanation:

Multiply 4 by 76, 77, and 78.

4 * 76 = 304

4 * 77 = 308

4 * 78 = 312

304 = 304, so C is the correct answer.

Hope this helps!

7 0

3 years ago

Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

fomenos

Answer:

$\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1$

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is $2a=|4--10|$ .

$\implies 2a=|14|$

$\implies 2a=14$

$\implies a=7$

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is $(\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)$

We need to use the relation $a^2+b^2=c^2$ to find $b^2$ .

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

$c=|6--3|=9$

$\implies 7^2+b^2=9^2$

$\implies b^2=9^2-7^2$

$\implies b^2=81-49$

$\implies b^2=32$

We substitute these values into the standard equation of the hyperbola to obtain:

$\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1$

$\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1$

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3 years ago