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stira [4]
2 years ago
5

Use properties to rewrite the given equation. Which equations have the same solution as 2.3p – 10.1 = 6.5p – 4 – 0.01p? Select t

wo options. 2.3p – 10.1 = 6.4p – 4 2.3p – 10.1 = 6.49p – 4 230p – 1010 = 650p – 400 – p 23p – 101 = 65p – 40 – p 2.3p – 14.1 = 6.4p – 4
Mathematics
1 answer:
Anna11 [10]2 years ago
5 0

The equations have the same solution are 2.3p – 6.5p + 0.01p =– 4  + 10.1 and -4.19p = 6.1

<h3>linear equation</h3>

This are equations that has a leading degree of 1. GIven the expression as shown below

2.3p – 10.1 = 6.5p – 4 – 0.01p

Collect the like terms

2.3p – 6.5p + 0.01p =– 4  + 10.1

Simplify

-4.19p = 6.1

Hence the equations have the same solution are 2.3p – 6.5p + 0.01p =– 4  + 10.1 and -4.19p = 6.1

Learn more on linear equation here: brainly.com/question/1884491

#SPJ1

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1.<br> Write a polynomial function in factored form with zeros at -2, 5, and 6.
Hatshy [7]

Answer:

f(x) = (x + 2) (x − 5) (x − 6)

Step-by-step explanation:

f(x) = (x − (-2)) (x − 5) (x − 6)

f(x) = (x + 2) (x − 5) (x − 6)

4 0
3 years ago
Jimmy began deriving the quadratic formula as shown. ax² +bx +c = 0 x2+bax+ca=0 x2+bax=−ca x2+bax+(b2a)2=−ca+(b2a)2 What should
andrew11 [14]
Factor the trinomial

8 0
3 years ago
The remainder obtained when 3x^3 - 6x^2 + ax -1 is divided by x+1 is equal to the remainder obtained when the same expression is
telo118 [61]

Answer:

5a

Step-by-step explanation:

Solution

verified

Verified by Toppr

We have x

3

−ax

2

+6x−a

Apply remainder theorem

x−a=0

x=a

Put x=a in equation.

(a)

3

−a(a)

2

+6a−a

=a

3

−a

3

+6a−a

=6a−a

=5a

Then reminder is 5a

4 0
3 years ago
I’m currently working on my quadrilaterals unit (specifically with trapezoids &amp; kites) and I need major help on a lot of the
allochka39001 [22]

Answer: 29.2

Step-by-step explanation:

The lengths of the two longer legs are both \sqrt{8^2 + 4^2}=\sqrt{80}

The lengths of the two shorter legs are both \sqrt{4^2+4^{2}}=\sqrt{32}

So P=2\sqrt{80}+2\sqrt{32} \approx 29.2

5 0
3 years ago
Read 2 more answers
Use the discriminant to describe the roots of each equation. Then select the best description. 2 = x2 + 5x. A) Double root B) Re
fredd [130]

\bf 2=x^2+5x\implies 0=x^2+5x-2\\\\\\\qquad \qquad \qquad \textit{discriminant of a quadratic}\\\\\\0=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+5}x\stackrel{\stackrel{c}{\downarrow }}{-2}~~~~~~~~\stackrel{discriminant}{b^2-4ac}=\begin{cases}0&\textit{one solution}\\positive&\textit{two solutions}\\negative&\textit{no solution}\end{cases}\\\\\\(5)^2-4(1)(-2)\implies 25+8\implies 33


so we have a 33, namely two real solutions for that quadratic.


usually that number goes into a √, if you have covered the quadratic formula, you'd see it there, namely that'd be equivalent to √(33), now 33 is a prime number, and √(33) is yields an irrational value, specifically because a prime number is indivisible other than by itself or 1.


so 33 can only afford us two real irrational roots.

3 0
3 years ago
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