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Ilya [14]
3 years ago
8

PLEASE HELP: A standard six-sided die is rolled.

Mathematics
1 answer:
amm18123 years ago
4 0

Answer in fraction form is 1/3

Answer in decimal form is 0.3333

Pick one answer only.

==========================================================

Explanation:

The sample space is the set of all possible outcomes. In this case, the outcomes consist of values between 1 and 6

S = sample space

S = {1,2,3,4,5,6}

There are 6 items here. Let B = 6.

We want to roll a number greater than 4, so the event space we're after is

E = {5,6}

which consists of 2 items. Let A = 2.

The probability we want is A/B = 2/6 = 1/3 = 0.3333

So if you go with the fraction option, then you'll type in 1/3

If you go with the decimal option, then you'll type in 0.3333

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Solve. 3 1/4 - 1 5/8
erik [133]

Step 1. Convert 3 1/4 to an improper fraction.

3 * 4 + 1/4 - 1 5/8

Step 2. Simplify 3 * 4 to 12

12 + 1/4 - 1 5/8

Step 3. Simplify 12 + 1 to 13

13/4 - 1 5/8

Step 4. Convert 1 5/8 to an improper fraction.

13/4 - 1 * 8 + 5/8

Step 5. Simplify 1 * 8 to 8

13/4 - 8 + 5/8

Step 6. Simplify 8 + 5 to 13

13/4 - 13/8

Step 7. Find the Least Common Denominator (LCD) of 13/4, 13/8

LCD = 8

Step 8. Make the denominators the same as the LCD

13 * 2/ 4 * 2 - 13/8

Step 9. Simplify. Denominators are now the same

26/8 - 13/8

Step 10. Join the denominators

26 - 13/8

Step 11. Simplify

13/8

Step 12. Convert to a mixed fraction

1 5/8


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3 years ago
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Please include the graphs!!!!!
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5(-6-3d)=3(8+7d)(if there is no solution,type in ''no solution'')d= Answer
swat32

In this question, you're solving for d.

Solve for d:

5(-6 - 3d) = 3(8+7d)

Use the distributive property:

-30 - 15d = 3(8+7d)

-30 - 15d = 24 + 21d

Add 30 to both sides:

-15d = 54 + 21d

Subtract 21d from both sides

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Divide both sides by -36

d = -3/2

Answer:

d = -3/2 or -1.5

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Construct a 99% confidthence interval for the population mean .Assume the population has a normal distribution. A group of 19 ra
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<h2>Answer with explanation:</h2>

Confidence interval for mean, when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean

n= sample size

s= sample standard deviation

t_{\alpha/2} = Critical t-value for n-1 degrees of freedom

We assume the population has a normal distribution.

Given, n= 19 , s= 3.8 , \overline{x}=22.4

\alpha=1-0.99=0.01

A) Critical t value for \alpha/2=0.005 and degree of 18 freedom

t_{\alpha/2} = 2.8784

B) Required confidence interval:

22.4\pm ( 2.8744)\dfrac{3.8}{\sqrt{19}}\\\\=22.4\pm2.5058\\\\=(22.4-2.5058,\ 22.4+2.5058)=(19.8942,\ 24.9058)\approx(19.9,\ 24.9)

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C) Interpretation: We are 99% confident that the true population mean of lies in (19.9, 24.9) .

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Answer:

Step-by-step explanation:

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