Answer:
1000 megabytes are in a gigabyte
Explanation:
Answer:
Explanation:
d(x) = -2x - 6
to find the inverse of a function, you need to follow these steps:
1. set d(x) = y
2. interchange the variables, so y becomes x and x becomes y
3. solve the equation for y
<u>step 1:</u> set d(x) = y
y = -2x -6
<u>step 2:</u> interchanging the variables
y = -2x - 6 turns into x = -2y - 6
<u>step 3:</u> solving for y
x = -2y - 6 < add 6 to both sides to get rid of it on the right
x + 6 = -2y < divide both sides by -2 to get y alone
x + 6 / -2 =
-2y / -2 = y
= y
so the inverse of the function is
Explanation:
There is a high degree of informality to these relationships, which are focused on information sharing, joint-problem solving and joint operations.
A hallmark of most of these processes is their informality, whether through information sharing, joint problem solving or joint operations.
Global joint problem-solving team. In addition to requesting a division of labour, the Global Task Team recommendations called upon the World Health Organization (WHO), UNICEF, the United Nations Population Fund (UNFPA), the United Nations Development Programme (UNDP), the World Bank, the UNAIDS Secretariat and the Global Fund to take the lead in and establish the joint United Nations system-Global Fund problem-solving team by July # in order to support efforts that address implementation bottlenecks at the country level
Answer:
See explaination for the program code
Explanation:
The code below
Pseudo-code:
//each item ai is used at most once
isSubsetSum(A[],n,t)//takes array of items of size n, and sum t
{
boolean subset[n+1][t+1];//creating a boolean mtraix
for i=1 to n+1
subset[i][1] = true; //initially setting all first column values as true
for i = 2 to t+1
subset[1][i] = false; //initialy setting all first row values as false
for i=2 to n
{
for j=2 to t
{
if(j<A[i-1])
subset[i][j] = subset[i-1][j];
if (j >= A[i-1])
subset[i][j] = subset[i-1][j] ||
subset[i - 1][j-set[i-1]];
}
}
//returns true if there is a subset with given sum t
//other wise returns false
return subset[n][t];
}
Recurrence relation:
T(n) =T(n-1)+ t//here t is runtime of inner loop, and innner loop will run n times
T(1)=1
solving recurrence:
T(n)=T(n-1)+t
T(n)=T(n-2)+t+t
T(n)=T(n-2)+2t
T(n)=T(n-3)+3t
,,
,
T(n)=T(n-n-1)+(n-1)t
T(n)=T(1)+(n-1)t
T(n)=1+(n-1)t = O(nt)
//so complexity is :O(nt)//where n is number of element, t is given sum
Answer:
I'm not exactly sure on what the question is, but from reading it, I determined that you'll be creating 2 different designs using Inkscape/Photoshop. I'm leaving 2 of my designs in here for you to use on your project. Unknown on what to do about the design that wasn't created in an image-editing program.
