According to the ethical computer use policy, users should be __________ of the rules and, by agreeing to use the system on that
1 answer:
You might be interested in
Answer:
Check the explanation
Explanation:
#include <stdio.h>
int dice1;
int dice2;
int sum;
int roll_die_twice(int dice1,int dice2){
if(sum==7){
printf("winner");
}
else if (sum==11){
printf("looser");
}
else if (sum!=7 && sum!=11)
{
printf("nor winner or looser");
}
}
int main()
{
roll_die_twice(2,7);
return 0;
}
The code screenshot and code output can be seen in the attached image below.
Answer:
is_even = 0
int_numbers = []
for n in range(4):
n = int(input('press any four integer numbers')
int_numbers.append(n)
for n in int_numbers:
if n%2==0:
print(n, 'integer is even')
is_even+= 1
else:
print(n, 'integer is odd')
print('Total even numbers =', is_even)
Explanation:
is_even = 0 (initiates a counter to record the number of even integers).
int_numbers creates a list to store the inputs entered by the user.
int(input()) : allows users to enter an integer number
int_numbers.append(n) : adds user input to list list variable created.
n%==2 : checks if entered digit leaves a remainder of 0 when divided by 2; hence an even number
is_even+= 1: counter updates by 1 for every even number confirmed.
