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koban [17]
2 years ago
8

Which command could you use to change to the /usr directory using a relative pathname?

Computers and Technology
1 answer:
swat322 years ago
6 0

Answer:

To change directories, use the cd command. This command by itself will always return you to your home directory; moving to any other directory requires a pathname. You can use absolute or relative pathnames.

Explanation:

I hope it's help

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The part of the poppet valve that contacts the valve seat is called the A. face. B. margin. C. head. D. stem.
Phantasy [73]
It should be A face, I think
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The number of __________ to your website that had not visited prior to the time frame being analyzed.
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Answer:

First Time Unique Visitor

Explanation:

I majored in

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In a relational database, the three basic operations used to develop useful sets of data are:
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<span>Which is not a component of a database that describes how data is stored?</span>
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Find the root using bisection method with initials 1 and 2 for function 0.005(e^(2x))cos(x) in matlab and error 1e-10?
frutty [35]

Answer:

The root is:

c=1.5708

Explanation:

Use this script in Matlab:

-------------------------------------------------------------------------------------

function  [c, err, yc] = bisect (f, a, b, delta)

% f the function introduce as n anonymous function

%       - a y b are the initial and the final value respectively

%       - delta is the tolerance or error.

%           - c is the root

%       - yc = f(c)

%        - err is the stimated error for  c

ya = feval(f, a);

yb = feval(f, b);

if  ya*yb > 0, return, end

max1 = 1 + round((log(b-a) - log(delta)) / log(2));

for  k = 1:max1

c = (a + b) / 2;

yc = feval(f, c);

if  yc == 0

 a = c;

 b = c;

elseif  yb*yc > 0

 b = c;

 yb = yc;

else

 a = c;

 ya = yc;

end

if  b-a < delta, break, end

end

c = (a + b) / 2;

err = abs(b - a);

yc = feval(f, c);

-------------------------------------------------------------------------------------

Enter the function in matlab like this:

f= @(x) 0.005*(exp(2*x)*cos(x))

You should get this result:

f =

 function_handle with value:

   @(x)0.005*(exp(2*x)*cos(x))

Now run the code like this:

[c, err, yc] = bisect (f, 1, 2, 1e-10)

You should get this result:

c =

   1.5708

err =

  5.8208e-11

yc =

 -3.0708e-12

In addition, you can use the plot function to verify your results:

fplot(f,[1,2])

grid on

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3 years ago
Explain the principles of computer applications ​
9966 [12]

Answer:

The nature of computers and code, what they can and cannot do.

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Necessary jargon: bits, bytes, megabytes, gigabytes.

How software works: what is a program, what is "running"

How digital images work.

Computer code: loops and logic.

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