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OLEGan [10]
4 years ago
11

Area of rectangle 12ft 6ft

Mathematics
1 answer:
Brilliant_brown [7]4 years ago
8 0
12ft×6ft= area of 72ft
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Can someone help me solve<br> (5x^2+3x+4)-(2x^2+5x-1)
djverab [1.8K]

Answer:

5x^2 + 3x + 4 - 2x^2 - 5x + 1

3x^2 - 2x + 5

Step-by-step explanation:

5 0
3 years ago
Find the original price before discount if discount is 25% and original price $25​
Lera25 [3.4K]

Answer:

umm im kinda confused but this may be the answer if you clarified.

25 is the answer after the discount but before the discount it would be  31.25 beccause...

Step-by-step explanation:

25 percent of 25= 6.25 so

6.25 plus 25= 31.25

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4 0
3 years ago
I need a specific explanation of how to answer this
zimovet [89]
A rectangle has two dimensions, width and length, and the area of it is their product.

since we know its area is 3x²-11x-4, then the two factors from that trinomial are the likely width and length, namely (3x + 1) (x - 4).

you can check them with FOIL.
5 0
3 years ago
Consider this equation. Cos(0) = 8/9 if 0 is an angle in quadrant IV, what is the value of tan(0)? I
Vinvika [58]

Answer:

\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}

Step-by-step explanation:

We are given that:

\displaystyle \cos(\theta)=\frac{8}{9}

Where θ is in QIV.

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Recall that cosine is the ratio of the adjacent side over the hypotenuse.

Therefore, the opposite side is:

o=\sqrt{9^2-8^2}=\sqrt{17}

Next, in QIV, only cosine is positive: sine and tangent are both negative.

Tangent is the ratio of the opposite side to the adjacent. So:

\displaystyle \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}

Substitute. Tangent is negative in QIV. Hence:

\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}

3 0
3 years ago
E<br> Ffgggggggyhhuhbgfd
Whitepunk [10]

Answer:

oh hello.

Step-by-step explanation:

7 0
3 years ago
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