Answer:
Step-by-step explanation:
the transverse axis is horizontal.
so its a horizontal hyperbola
Center is the origin so center is (0,0)
Equation of horizontal hyperbola is
Given a= 55000 and c= 81000
c^2 = a^2 + b^2
81000^2 = 55000^2 + b^2
subtract 55000^2 on both sides
b = sqrt(81000^2 - 55000^2)= 59464.27
now plug in the values
The equivalence
means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417
Answer:
okay let's start
Step-by-step explanation:
Answer:
Resulting equation will be 5x²=36.
Step-by-step explanation:
The given equations are 5y = 10x-----(1)
and x²+y²=36------(2)
Now we substitute the value of y from equation (1) into equation (2).
5y = 10x ⇒ y = 2x
Then equation (2) will be x²+(2x)²=36
x²+4x²=36 ⇒ 5x² = 36
So the equation after substitution of the value of y from equation 1 will be 5x² = 36.