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igor_vitrenko [27]

3 years ago

14

How do i turn into a mermaid

2 answers:

kenny6666 [7]3 years ago

7 0

Brush your hair with a fork and sing a lot

Eduardwww [97]3 years ago

3 0

Answer:

swim alot ig and do what they said up there

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If kc = 0.143 at 25°c for this reaction, predict the direction in which the system will shift if the initial concentrations of c

GenaCL600 [577]

The equation is as follows:
Cyclohexane (C6H12) ⇔ Methyl cyclopentane (C6H12)
The equilibrium constant Kc = 0.143 >>> (1)
Qc is the reaction quotient
where; If Q = K >>>> No shift left or right >>> (2)
Q > K >>>> Reaction shifts left >>> (3)
Q < K >>>> Reaction shifts right >>> (4)
And in our equation; Q = 0.3 / 0.4 = 0.75 >>> (5)
From (1), (3) and (5), Q > Kc
∴ the reaction shifts left

3 0

3 years ago

ANSWER FAST PLZ 25 POINTS!!!!!!!!!!!!!!!

Viktor [21]

Answer:

c.

Explanation:

not to positive but I hope this is correct ‍♀️

4 0

4 years ago

I need number 5,6 please thanks

bulgar [2K]

5. b is the right answer

6. c is the right answer

6 0

3 years ago

A 21.8 g sample of ethanol (C2H5OH) is burned in a bomb calorimeter, according to the following reaction. If the temperature ris

Blababa [14]

<u>Answer:</u> The heat capacity of calorimeter is $15.66J/^oC$

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of ethanol = 21.8 g

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

$\text{Moles of ethanol}=\frac{21.8g}{46.07g/mol}=0.473mol$

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

$q$ = amount of heat released = ?

n = number of moles = 0.473 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -1235 kJ/mol = $-1235\times 10^3J/mol$ (Conversion factor: 1 kJ = 1000 J)

Putting values in above equation, we get:

$-1235\times 10^3J/mol=\frac{q}{0.473mol}\\\\q=(-1235\times 10^3J/mol\times 0.473mol)=-584.16\times 10^3J$

To calculate the heat capacity of calorimeter, we use the equation:

$q=c\Delta T$

where,

q = heat absorbed by the calorimeter = $584.16\times 10^3J$

c = heat capacity = ?

$\Delta T$ = change in temperature = $T_2-T_1=62.3^oC-25^oC=37.3^oC$

Putting values in above equation, we get:

$584.16\times 10^3J=c\times 37.3^oC\\\\c=\frac{584.16\times 10^3J}{37.3^oC}=15.66J/^oC$

Hence, the heat capacity of calorimeter is $15.66J/^oC$

4 0

4 years ago

What is the pH of a solution with an OH- ion concentration of 4.01E-4?

Ber [7]

Answer:

[H]=10^-4 when ph=4 higher

[H]=10^-5 when ph =5 lower

Explanation:

brains

8 0

3 years ago