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iris [78.8K]
3 years ago
8

HELLLPPPP!!!!

Chemistry
1 answer:
AleksAgata [21]3 years ago
6 0
A. Because you have to simplify
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In a controlled scientific experiment,​
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D

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For It to be controlled more than one variable has to stay the same

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Higher volumes of water can carry greater loads.<br> true<br> false
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calculate the volume od a CO2 cartridge that has a pressure of 850 PSI at a temperature of 21ºc the cartridge contains 0.273 mol
gladu [14]
Answer is: volume of CO₂ is 0,113 dm³.
Ideal gas law = pV = nRT.
p = 850 PSI = 5860543,6992 Pa.
Psi <span>is the abbreviation of pound per square inch.
T = 21</span>°C = 294,15 K.
n = 0,273 mol.
R = 8,314 J/K·mol.
V = nRT ÷ p
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What is unique about the size and location of this exoplanet?
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An unknown concentration of sodium thiosulfate, Na2S2O3, is used to titrate a standardized solution of KIO3 with excess KI prese
Maru [420]

Answer: The molarity of Na_2S_2O_3 is 0.108 M

Explanation:

KIO_3+5KI+3H_2SO_4\rightarrow 3K_2SO_4+3H_2O+3I_2

2Na_2S_2O_3+I_2\rightarrow Na_2S_4O_6+2NaI

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}    

\text{Moles of }KIO_3=\frac{0.0131mol/L\times 21.55}{1000}=2.8\times 10^{-4}mol

1 mole of KIO_3  produces = 3 moles of   I_2

2.8\times 10^{-4} moles of KIO_3 produces = \frac{3}{1}\times 2.8\times 10^{-4}=8.4\times 10^{-4} moles of I_2  

Now 1 mole of I_2 uses = 2 moles of Na_2S_2O_3

8.4\times 10^{-4} moles of I_2 uses =  \frac{2}{1}\times 8.4\times 10^{-4}=1.69\times 10^{-3}  moles of Na_2S_2O_3

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}=\frac{1.69\times 10^{-3}\times 1000}{15.65}=0.108M

The molarity of Na_2S_2O_3 is 0.108 M  

6 0
3 years ago
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