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3 years ago

Calculate the density of argon gas at a pressure of 753 mmHg and a temperature of 35 °C

1 answer:

3 0

PV=nRT
PV= (m/M)RT
PM=(m/v)RT
PM =dRT
d= (PM) ÷(RT)

substitute the the given data to the above equation. d-density, p-pressure, M- molar mass of argon gas, T- temperature. and R is a constant. make sure to substitute its value too.. :)

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A hiker seals a plastic bag that contains dried fruit before the climbs a mountain. What will most likely happen to the plastic

romanna [79]

From the ideal gas equation,

$PV = nRT$

where n is number of moles, R is Universal gas constant, P is pressure, V is volume, and T is temperature of the gas.

The pressure and volume are inversely proportional to each other at constant temperature and number of moles.

Hence, on decreasing the pressure, the volume will increase.

As the hiker reaches a height of a mountain, the pressure would decrease which results in the reestablishment of equilibrium between gas molecules thus resulting in pushing of bag outwards.

Hence, the bag will expand as the hiker reaches the top of the mountain.

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2 years ago

Methane undergoes combustion. Which products form?

Aleksandr [31]

Methane is a carbon compound which undergoes combustion to release energy and form bi production which are Carbon dioxide ( CO2 ) and  Water ( H20 ).

the balanced chemical equation for the reaction is : -

CH4 + 2 O2 =》CO2 + 2 H2O

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3 years ago

Which stimulus is an example of an internal stimulus?

lawyer [7]

An example of an external stimulus is a decrease in oxygen levels in the blood during exercise.

Option C

<h3>What is stimulus?</h3>

A stimulus is defined as a thing or sensation that causes a specific reaction in an organ or tissue of a living organism

There are two types of stimuli:

Internal stimulus
External stimulus

Learn more about stimulus:

brainly.com/question/20117556

3 0

2 years ago

Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu

ad-work [718]

Initial volume of the balloon = $V_{1}$ = 348 mL

Initial temperature of the balloon $T_{1}$ = $25.0^{0}C + 273 = 298 K$

Final volume of the balloon $V_{2}$ = 322 mL

Final temperature of the balloon = $T_{2} = ?$

According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.

$\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }$

On plugging in the values,

$\frac{348mL}{298 K} =\frac{322 mL}{T_{2} }$

$T_{2} =276 K$

Therefore, the temperature of the freezer is 276 K

5 0

3 years ago

When 21.45 g of KNO3 was dissolved in water in a calorimeter, the temperature fell from 25.00°C to 14.14 °C. If the heat capacit

pashok25 [27]

25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)

<h3>Explanation</h3>

The process:

$\text{KNO}_3\;(s) \to \text{KNO}_3\;(aq)$ .

How many moles of this process?

Relative atomic mass from a modern periodic table:

K: 39.098;
N: 14.007;
O: 15.999.

Molar mass of $\text{KNO}_3$ :

$M(\text{KNO}_3) = 39.098 + 14.007 + 3\times 15.999 = 101.102\;\text{g}\cdot\text{mol}^{-1}$ .

Number of moles of the process = Number of moles of $\text{KNO}_3$ dissolved:

$\displaystyle n = \frac{m}{M} = \frac{21.45}{101.102} = 0.212162\;\text{mol}$ .

What's the enthalpy change of this process?

$Q = C\cdot \Delta T = 0.505 \times (25.00 - 14.14) = 5.4843\;\text{kJ}$ for $0.212162\;\text{mol}$ . By convention, the enthalpy change $\Delta H$ measures the energy change for each mole of a process.

$\displaystyle \Delta H = \frac{Q}{n} = \frac{5.4843\text{kJ}}{0.212162\;\text{mol}} = 25.8\;\text{kJ}\cdot\text{mol}^{-1}$ .

The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

4 0

3 years ago