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Readme [11.4K]
3 years ago
7

Calculate the density of argon gas at a pressure of 753 mmHg and a temperature of 35 °C

Chemistry
1 answer:
ycow [4]3 years ago
3 0
PV=nRT
PV= (m/M)RT
PM=(m/v)RT
PM =dRT
d= (PM) ÷(RT)

substitute the the given data to the above equation. d-density, p-pressure, M- molar mass of argon gas, T- temperature. and R is a constant. make sure to substitute its value too.. :)
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One method used commercially to peel potatoes is to soak them in a solution of NaOH for a short time and then remove them from t
sergij07 [2.7K]

Answer:

b. 2.28 M

Explanation:

The reaction of neutralization of NaOH with H2SO4 is:

2NaOH + H2SO4 → Na2SO4 + 2H2O

<em>Where 2 moles of NaOH react per mole of H2SO4</em>

<em />

To solve the concentration of NaOH we need to find the moles of H2SO4. Using the chemical equation we can find the moles of NaOH that react and with the volume the molar concentration as follows:

<em>Moles H2SO4:</em>

45.7mL = 0.0457L * (0.500mol/L) = 0.02285 moles H2SO4

<em>Moles NaOH:</em>

0.02285 moles H2SO4 * (2moles NaOH / 1 mol H2SO4) = 0.0457moles NaOH

<em>Molarity NaOH:</em>

0.0457moles NaOH / 0.020L =

2.28M

Right option:

<h3>b. 2.28 M</h3>
7 0
3 years ago
The reaction can be described using the equation: 2C2H25O24CO22H2O. How much C2H2is needed to react with 68.1 g of O2to produce
Sophie [7]

Answer:

22.13g

Explanation:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Next, we'll calculate the mass of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H2 = (12x2) + (2x1)

= 24 + 2 = 26g/mol

Mass of C2H2 that reacted from the balanced equation = 2 x 26 = 52g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 5 x 32 = 160g

Now, we can obtain the mass of C2H2 that will react with 68.1g of O2 as follow:

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Therefore, Xg of C2H2 will react with 68.1g of O2 i.e

Xg of C2H2 = (52x68.1)/160

Xg of C2H2 = 22.13g

Therefore, 22.13g of C2H2 is needed to react with 68.1g of O2

8 0
3 years ago
Wood is mainly cellulose, a polymer produced by plants. One use of wood is as a fuel in campfires, fireplaces, and wood furnaces
Alja [10]

Answer:

C6 H10 O5+ 6O2-----> 6CO2+5H2O+heat

Explanation:

There are 6 carbon atoms in reactants to balance you put coefficient 6.

This makes the oxygen in CO2 12 so to balance put 6 in oxygen in reactants.

There are 10 hydrogen atoms in reactants to balance you put 5 in front of H2O in products.

If u recheck: 6 C atoms in reactants, 6 C atoms in products.

10 H atoms in reactants, 10 H atoms in products.

17 O atoms in reactants, 17 O atoms in products.

6 0
2 years ago
2 Use the chart to answer the question. Solubility Curves of Various Salts 180 160 140 120 100 80 KNO3 in g NaCl in g KCl in g A
VMariaS [17]

According to the information in the graph, it can be inferred that the amount of solute that will precipitate out of solution at 20°C is 130 grams.

<h3>How to calculate the amount of solute that precipitates out of solution?</h3>

To calculate the amount of solute that precipitates out of solution we must identify the solute data at 80°C and 20°C and identify the difference as shown below:

  • Quantity of solute at 80°C: 170 grams.
  • Quantity of solute at 20°C: 40 grams.

  • 170 grams - 40 grams = 130 grams

According to the above, the amount of solute that will precipitate out of solution due to the change in temperature is 130 grams of KNO3.

Note: This question is incomplete because the graph is missing. Here is the graph

Learn more about solute in: brainly.com/question/7932885

#SPJ1

7 0
2 years ago
What process describes the transfer of heat through matter by molecular activity?
DIA [1.3K]
The process that describes the transfer of heat through matter by activity of the molecules would be conduction. This type of heat transfer due to the motion of electrons and ions. within a body. As molecules collide with each energy is transferred and released which cause temperature to rise or drop.<span />
8 0
4 years ago
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