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vampirchik [111]
3 years ago
12

Round 82736 to 1 significant figure

Mathematics
1 answer:
hram777 [196]3 years ago
5 0

Answer:

80000

Step-by-step explanation:

Significant figures are any number but zeroes.

However, in some cases, zeroes also count as significant figures.

  • Zeroes are significant figures when between other non-zero numbers.
  • Zeroes are significant when you see a dot on the right indicating that zero is not a place holder.
  • They are <u>not</u> significant when serving as place holders, such as zeroes on the right side of a number. For example, .004 has 1 sig fig. The 2 zeroes on the left aren't sig figs because they're just place holders.
  • Zeroes on the <u>right</u> side of a decimal are also significant.

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73,127,849 rounded to the nearest ten
Marat540 [252]

The next larger ten is . . . . . . 50 .
The next smaller ten is . . . . . . 40 .

. . . . . . 49  is closer to . . . . . . 50  than it is to . . . . . . 40 .

So the nearest ten is . . . . . . 50 .

4 0
4 years ago
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An animal shelter spends $2.35 per day for each cat and $5.50 per day to care for each dog. Pat noticed that the shelter spent $
Nadusha1986 [10]
Lets use the letter C to represent cats and D to represent dogs.

A)     2.35c + 5.50d = 89.50

For B, they give you numbers to plug into your equation.
c = 8
d= 14

B) 2.35(8) + 5.50(14) = 89.50
     18.80 + 77.00 = 95.80

So what Pat said is incorrect because that would mean they spent more than 89.50.

Hope this helps! :)
6 0
4 years ago
Complete the statements about the key components of the hyperbola shown. The distance, a, between the center and each vertex is
Aloiza [94]

Answer:

A.4  B.5  C.3  D.4/3

Step-by-step explanation:

i just did it

3 0
4 years ago
The Pirerras are planning to go to Europe 3 years from now and have agreed to set aside $140/month for their trip. If they depos
Natalka [10]

Answer:

(a)$5805.21

(b)Least Expensive Mortgage =$120640.59

Most Expensive Mortgage =$152032.77

Step-by-step explanation:

The future value of an ordinary annuity with deposits P made regularly k times each year for n years, with interest compounded times k per year at an annual rate r, is given as:

F.V.=\dfrac{P[(1+i)^{kn}-1]}{i}

The Pirerra's Monthly Payments=$140

Annual Rate =9.5%

Therefore: Monthly Rate=0.095/12

Years, n=3

Period, k=12

F.V.=\dfrac{140[(1+\frac{0.095}{12} )^{3*12}-1]}{\frac{0.095}{12} }=\$5805.21

(b)For the Johnsons, Present value of Mortgage is derived using the formula:

\Text{Present Lump Sum}, A_0=\dfrac{P[1-(1+i)^{-kt}]}{\frac{r}{k} }

At $1000 Monthly payment

\Text{Present Lump Sum}, A_0=\dfrac{1000[1-(1+\frac{0.08}{12} )^{-12*15}]}{\frac{0.08}{12} }=\$104640.59

Adding  a down payment of $16000

  • Least Expensive Mortgage = 104640.59+16000=$120640.59

At $1300 Monthly Payment

\Text{Present Lump Sum}, A_0=\dfrac{1300[1-(1+\frac{0.08}{12} )^{-12*15}]}{\frac{0.08}{12} }=\$136032.77

Adding  a down payment of $16000

  • Most Expensive Mortgage = 136032.77+16000=$152032.77
4 0
3 years ago
A and b are independent. calculate p(a or<br> b.if p(a) = 0.22 and p(b) = 0.24.
ziro4ka [17]
If events A and B are independent, 
For mutually exclusive then  p(A or B) = p(A) + p(B).

For not mutually exclusive then p(A or B) = p(A) + p(B) - p(A and B)
And:        p(A and B) = p(A) * p(B)


Given: <span>p(A) = 0.22 and p(B) = 0.24.
</span>
<span>∴ p(A and B) = p(A) * p(B) = 0.22*0.24 = 0.0528
</span>

If A and B are mutually exclusive
∴ p(A or B) = p(A) + p(B) = 0.22 + 0.24 = 0.46

If A and B are not mutually exclusive
∴ p(A or B) = p(A) + p(B) - p(A and B) = 0.22 + 0.24 - <span>0.0528 = 0.4072
</span>
=============================================

note: Two events are mutually exclusive if it is not possible for both of them to occur, which mean the occurrence of one event "excludes" the possibility of the other event.
4 0
3 years ago
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