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vampirchik [111]
3 years ago
12

Round 82736 to 1 significant figure

Mathematics
1 answer:
hram777 [196]3 years ago
5 0

Answer:

80000

Step-by-step explanation:

Significant figures are any number but zeroes.

However, in some cases, zeroes also count as significant figures.

  • Zeroes are significant figures when between other non-zero numbers.
  • Zeroes are significant when you see a dot on the right indicating that zero is not a place holder.
  • They are <u>not</u> significant when serving as place holders, such as zeroes on the right side of a number. For example, .004 has 1 sig fig. The 2 zeroes on the left aren't sig figs because they're just place holders.
  • Zeroes on the <u>right</u> side of a decimal are also significant.

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Answer:

Data set B has a higher range than data set A and thus B has a higher degree of variability than A.

Step-by-step explanation:

There are several measures of variability in Statistics among them being;

The range

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To compare the variability of two or more sets of data, we can compute any of the above measures of dispersion and compare them across the various data sets.

In this question we have been given two data sets;

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The simplest measure of variability or dispersion is the range. The range is defined as the difference between the maximum and the minimum values in a data set.

The range of data set A is; 39 - 18 = 21

The range of data set B is; 52 - 26 = 26

Data set B has a higher range than data set A and thus B has a higher degree of variability than A.

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Find the equation, f(x) = a(x-h)2 + k, for a parabola that passes through the point (1,-7) and has (2,- 4) as its vertex. What i
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(h;\ k)\ -\ \text{the coordinates of the vertex}

\text{therefore we have}\ f(x)=a(x-2)^2-4
 
<span>\text{a parabola that passes through the point (1,-7)}

</span><span>\text{substitute the coordinates of the point (1;-7) to the equation:}

(1;-7)\to x=1;\ y=-7\\\\-7=a(1-2)^2-4\\\\-7=a(-1)^2-4\\\\-7=a-4\ \ \ |+4\\\\a=-3

</span><span>
</span>Answer:\ \text{c.The vertex form of the equation is}\ f(x)=-3(x-2)^2-4.\\\text{The standard form of the equation is}\ f(x)=-3x^2+12x-16
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