Answer:
65 degrees
Step-by-step explanation:
Break the parallelogram up into two triangles. Angle E is 70 degrees and 45 degrees because of the property of equal opposite angles. So E 45 degrees Y 70 degrees and if you add the two up you get 115 degrees. There are 180 degrees in a triangle, so 180-115=65.
Answer:
(a) 0.2061
(b) 0.2514
(c) 0
Step-by-step explanation:
Let <em>X</em> denote the heights of women in the USA.
It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.
(a)
Compute the probability that the sample mean is greater than 63 inches as follows:
![P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z](https://tex.z-dn.net/?f=P%28%5Cbar%20X%3E63%29%3DP%28%5Cfrac%7B%5Cbar%20X-%5Cmu%7D%7B%5Csigma%2F%5Csqrt%7Bn%7D%7D%3E%5Cfrac%7B63-64%7D%7B3%2F%5Csqrt%7B6%7D%7D%29%5C%5C%5C%5C%3DP%28Z%3E-0.82%29%5C%5C%5C%5C%3DP%28Z%3C0.82%29%5C%5C%5C%5C%3D0.20611%5C%5C%5C%5C%5Capprox%200.2061)
Thus, the probability that the sample mean is greater than 63 inches is 0.2061.
(b)
Compute the probability that a randomly selected woman is taller than 66 inches as follows:
![P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E66%29%3DP%28%5Cfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cfrac%7B66-64%7D%7B3%7D%29%5C%5C%5C%5C%3DP%28Z%3E0.67%29%5C%5C%5C%5C%3D1-P%28Z%3C0.67%29%5C%5C%5C%5C%3D1-0.74857%5C%5C%5C%5C%3D0.25143%5C%5C%5C%5C%5Capprox%200.2514)
Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.
(c)
Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:
![P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0](https://tex.z-dn.net/?f=P%28%5Cbar%20X%3E66%29%3DP%28%5Cfrac%7B%5Cbar%20X-%5Cmu%7D%7B%5Csigma%2F%5Csqrt%7Bn%7D%7D%3E%5Cfrac%7B66-64%7D%7B3%2F%5Csqrt%7B100%7D%7D%29%5C%5C%5C%5C%3DP%28Z%3E6.67%29%5C%5C%5C%5C%5C%20%3D0)
Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.
SOH CAH TOA tells you
Cos(x) = Adjacent/Hypotenuse
so you can find
x = arccos(24/28)
x ≈ 31.0°
Answer: m< MIH is 34°
M< AVM is 70°
And the angle of the obtuse angle formed at the intersection of AV and HI is 104°
Step-by-step explanation: starting with m<MIH, AH is parallel to MI, so that would make the same angle H has the same for I. (34°)
Next is m<AVM. The angle of m<LAH is 110°. So the angle of m<HAV (because it's supplementary of it) is 70 (110+70=180). Which makes m<AVM 70° since it's vertical to each other.
Since we got those answers, the next one you just plug it in, and the answer would be 104°
If 2160= 2^a3^b5^c the solution set of a,b,c is<br>{4,3,0}<br>{1,0,3}<br>{4,3,1}<br>{2,3,4}
Readme [11.4K]
Answer:
4,3,1
Step-by-step explanation:
2^a3^b5^c=2160
2^a3^b5^c=2^4 3^3 5^1
a=4,b=3 and c=1