Answer:
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Step-by-step explanation:
Answer:
1/3
Step-by-step explanation:
Answer:
21
Here’s legitimate proof that 9+10=21
(9 + 10) (base x) = 21 (base y)
9(1) + [1(x) + 0(1)] = 2(y) + 1
Simplify and solve for y:
2y = 8 + x
y = 4 + x/2
Since we have number bases, we want x and y to be positive integers. The term x/2 requires that x be a positive even number.
Also since 9 is in base x, we have x ≥ 10, as the digit 9 would not be used for a base 9 or smaller.
Thus we have the pairs of solutions:
x = 10, so y = 9
x = 12, so y = 10
x = 14, so y = 12
…
x, y = 4 + x/2 … Therefore 9+10=21!
Answer:
(x +9) ^2 + (y +7)^2 = 289
Step-by-step explanation:
We know the equation of a circle can be written as
(x-h) ^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius
We are given the diameter so we can find the radius
r = d/2 = 34/2 = 17
(x- -9) ^2 + (y- -7)^2 = 17^2
(x +9) ^2 + (y +7)^2 = 17^2
(x +9) ^2 + (y +7)^2 = 289
Answer:
The perfect square ( x -1 )² = 2
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given equation x² - 2 x = 1
⇒ x² - 2 x + 1 -1 = 1
⇒ x² - 2x + 1² = 1 +1
⇒ ( x -1 )² = 2
