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3 years ago

Ok help me plsssssssss

Mathematics

2 answers:

vichka [17]3 years ago

7 0

A :)))))))))(())))))))))))))))))

Nady [450]3 years ago

4 0

Answer:

the answer is a)

Step-by-step explanation:

sorry i don't what to explain here

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5. You answered 21 out of 25 questions correctly on a test. Did you reach your goal of getting at least 80%?

hichkok12 [17]

Answer:

You scored more than 80 %

Step-by-step explanation:

21/25

We need to change this to a decimal, then to a percent

21/25 *4/4 = 84/100

This is out of 100 so it is 84%

84>80.

You scored more than 80 %

6 0

4 years ago

Read 2 more answers

What is the equation of the line that passes through (4,3) and (2, -1)?

jeka94

Answer:

y = 2x - 5

Step-by-step explanation:

Step 1: Find slope m

m = (-1 - 3)/(2 - 4)

m = -4/-2

m = 2

y = 2x + b

Step 2: Find b

-1 = 2(2) + b

-1 = 4 + b

b = -5

Step 3: Rewrite equation

y = 2x - 5

4 0

4 years ago

On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t

Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is $V_{hc}=-8\hat{i}-6\hat{k}$

The angle at which hailstones falling relative to the cyclist is $\theta = 36.86^\circ$

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of $2\hat{i}-6\hat{k}\text{ m/s}$ . If a cyclist travels through the hail at $10\hat{i} \text{ m/s}$ .

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is $V_h=2\hat{i}-6\hat{k}\text{ m/s}$

The velocity of the cyclist travels through the hail is $V_c=10\hat{i} \text{ m/s}$

The velocity of the hail relative to the cyclist is given by,

$V_{hc}=V_h-V_c$

Substitute the value in the formula,

$V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}$

$V_{hc}=-8\hat{i}-6\hat{k}$

So, The velocity of the hail relative to the cyclist is $V_{hc}=-8\hat{i}-6\hat{k}$

Now, The angle of hails falling relative to the cyclist is given by

$\theta = \tan^{-1}(\frac{-6}{-8})$

$\theta = \tan^{-1}(\frac{3}{4})$

$\theta = 36.86^\circ$

So, The angle at which hailstones falling relative to the cyclist is $\theta = 36.86^\circ$

4 0

4 years ago

A baby pool is shaped like a short, wide cylinder and holds 52 ft3 of water. A medium pool measures 4 times the height and width

otez555 [7]

The volume of a cylinder is the area of the base, times the height.
The area of the circular base is, of course, π times the square of its radius. 
So the volume of a cylinder, V, is 
V = π h r^2 
where h is the height and r is the radius. 

If we multiply the height by 3, the new height is 3h. 
If we multiply the width by 3, that multiplies the radius (which is half the width) by 3 also. 
So the new volume would be 
π (3h) (3r)^2 = π (3h) (9r^2) = 27π h r^2 
which is 27 times π h r^2, the volume of the smaller pool. But we know that volume is 37 cubic feet. 

So the volume of the larger pool is 
27 * 37 cubic feet = 999 cubic feet [answer B] 

This is an instance of a general rule: 
If we multiply ALL the linear dimensions of an object by a factor F, 
while keeping the shape the same (often termed "similar" in geometry), 
that multiplies the volume by F^3 (the cube of F). 

It also multiplies the surface area by F^2. 

These rules are very useful, especially when you hit these questions on an exam under time constraints. If you know them, you'll save time you can use to work other questions.

3 0

3 years ago

Suppose you randomly select a letter from BURGER AND STARBIRD. Imagine writing these letters on Ping- Pong balls—one letter per

MaRussiya [10]

There are 17 possible letters you can choose from and 3 of them are "r"s. So, the probability is 3/17.

Hope this helps!

7 0

4 years ago