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dolphi86 [110]
3 years ago
5

A rectangular prism has a length of  1 1/4 centimeters, a width of 4 centimeters, and a height of 3 1/4centimeters.

Mathematics
2 answers:
V125BC [204]3 years ago
6 0

Answer:

The answers to this question are 1, 2 and 5

Step-by-step explanation:

Svetllana [295]3 years ago
3 0

Answer:

16.25 cubic cm

Step-by-step explanation:

The volume of a prism is found using V = l*w*h. Here l = 1.25, w = 4 and h = 3.25. Substitute and simplify.

V = 1.25(4)(3.25)

V = 16.25

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Answer:

4x + (–3) = 5x + 4

Step-by-step explanation:

i got it right on edge. :)

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Jack is 1.75 m tall and casts a shadow 2.25 m long. At the same time, a statue casts a shadow 9 m long. What is the height of th
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1.75 divided by 2.25 = 0.77777777...
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Choose all which define events A and B as independent events.
Firlakuza [10]

There are 2 answers: Choice 1, Choice 4

=======================================

Why is this? Because we use the rule

P(A & B) = P(A) * P(B)

which only works if events A and B are independent

----

For the first answer choice,

P(A) * P(B) = 0.6*0.4 = 0.24 = P(A & B)

so that matches.

The same applies to the fourth answer choice as well

P(A) * P(B) = 0.3*0.2= 0.06 = P(A & B)

----

The other answer choices don't match up.

The second answer choice has

P(A) * P(B) = 0.3*0.4 = 0.12 but that doesn't match with the 0.70 given

Similarly for the third answer choice,

P(A) * P(B) = 0.5*0.1 = 0.05 which doesn't match with the 0.60

3 0
3 years ago
The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l
mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: (\frac{n+1}{2}) th\ term

Putting n=21

(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

<u>For First Half:</u>

98, 100, 101, 102, <u>108, 109</u>, 111,118, 129, 132

Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5

<u>For Second Half:</u>

135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151

Now

<u>Interquartile Range:</u>

IQR = Q_3-Q_1\\= 151-108.5\\=42.5

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

  • brainly.com/question/10940255
  • brainly.com/question/10941043

#LearnwithBrianly

7 0
3 years ago
It is 90 ft from home plate to first base on a baseball diamond. How long will it take a batter to reach first base if the batte
vitfil [10]

Answer:

It would take the batter 6 seconds to reach 1st base

3 0
3 years ago
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