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2 years ago

Find the exact value of tan 0

Mathematics

2 answers:

sweet-ann [11.9K]2 years ago

8 0

Answer:

Tangent = Opposite/Adjacent

Tangent = 6/2 $\sqrt{5\\}$

Tangent = 3/ $\sqrt{5\\}$

Let me know if this helps!

Jet001 [13]2 years ago

6 0

Answer:

3√5/5

Step-by-step explanation:

tan 0= p/b
6/2√5
3√5/5

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My professor showed us in class today how to use ode45 to solve a differential equation numerically. i would like to use it on m

Brilliant_brown [7]

Yes, ode45 can be used for higher-order differential equations. You need to convert the higher order equation to a system of first-order equations, then use ode45 on that system.

For example, if you have

... u'' + a·u' + b·u = f

you can define u1 = u, u2 = u' and now you have the system

... (u2)' + a·u2 + b·u1 = f

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ode45 is used to solve each of these. Now, you have a vector (u1, u2) instead of a scalar variable (u). A web search regarding using ode45 on higher-order differential equations can provide additional illumination, including specific examples.

7 0

3 years ago

I need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)

Dahasolnce [82]

Five number summary and IQR of both the data sets are different.

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Part A:

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set into four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

The interquartile range of the data is

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

$IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =16-6.2\\ =9.5$

The interquartile range of the data is

$IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =15.5-8\\ =7.5$

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.

To learn more about the symmetric visit:

brainly.com/question/1002723

#SPJ1

6 0

2 years ago

Simplify the expression below.

olasank [31]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}
\\\\
-------------------------------\\\\$

$\bf \cfrac{14a^8y^3-7a^4y^5+28a^{12}y^2}{7a^4y}\impliedby 
\begin{array}{llll}
\textit{let us first, distribute}\\
the~denominator
\end{array}
\\\\\\
\cfrac{14a^8y^3}{7a^4y}-\cfrac{7a^4y^5}{7a^4y}+\cfrac{28a^{12}y^2}{7a^4y}
\\\\\\
\cfrac{14}{7}a^8a^{-4}y^{-1} y^3-\cfrac{7}{7}a^4a^{-4}y^{-1} y^5+\cfrac{28}{7}a^{12}a^{-4}y^{-1} y^2
\\\\\\
2a^{8-4}y^{-1+3}-1a^{4-4}y^{-1+5}+4a^{12-4}y^{-1+2}
\\\\\\
2a^4y^2-1\cdot 1y^4+4a^8y\implies 2a^4y^2-y^4+4a^8y$

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2 years ago

What is the midpoint of the line segment that joins (6-2) and (,5)

PIT_PIT [208]

Answer:

Step-by-step explanation:

X=(6,-2)

Y=(0,5)

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2 years ago

4 (x - 1) = }(12x – 3)

slamgirl [31]

Answer:

x= -1/8

Step-by-step explanation:

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2 years ago