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3 years ago

Explain why the difference of two polynomials will always be a polynomial

1 answer:

8 0

<span>They are finite sums of expressions of the form where a is a constant, x is the variable and k is a non-negative integer</span>

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3x - 4y = 18<br>x + 3y = -7

Mnenie [13.5K]

Answer:

x=2, y=-3

Step-by-step explanation:

x+3y+-7

move variable to the right and -3y from each side

x+3y-3y=-7-3y

x= -7-3y

3x -4y=18

3(-7-3y)-4y=18

solve for y, distribute

-21-9y-4y=18

collect like terms

-21-13y=18

move constant and change sign

-13y=18+21

add

-13y=39

divide by -13

y= -3

substitute

x=-7-3(-3)

solve

x=2

4 0

3 years ago

Simple interest on a bank loan can be calculated by multiplying the principal times the interest rate times the time. In the for

diamong [38]

Answer:

simple interest

Step-by-step explanation:

this is because r is interest rate, p is principal, and t is time

5 0

2 years ago

Read 2 more answers

The ratio of orange crayons to purple crayons is 2/4if there are 64 orange crayons the box how many purple crayons are there in

lesya692 [45]

2/4=1/2 two is 2 times greater than one so what is two times greater that 64?

64x2=128

6 0

3 years ago

Read 2 more answers

Someone pls help me!! Asap

LiRa [457]

Answer: Its on paper I can't solve it

Step-by-step explanation:

6 0

3 years ago

Suppose the weights of seventh‑graders at a certain school vary according to a Normal distribution, with a mean of 100 pounds an

alex41 [277]

Answer:

We conclude that there is no change in the average weight since the implementation of a new breakfast and lunch program at the school.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 100 pounds

Sample mean, $\bar{x}$ = 98 pounds

Sample size, n = 35

Alpha, α = 0.05

Population standard deviation, σ = 7.5 pounds

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 100\text{ pounds}\\H_A: \mu < 100\text{ pounds}$

We use one-tailed(left) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{98 - 100}{\frac{7.5}{\sqrt{35}} } = -1.577$

Now, $z_{critical} \text{ at 0.05 level of significance } = -1.64$

We calculate the p-value with the help of standard normal table.

P-value = 0.057398

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept is.

We conclude that there is no change in the average weight since the implementation of a new breakfast and lunch program at the school.

3 0

3 years ago